Answer:
<em>709.5 cal</em>
<em></em>
Explanation:
masa m de la barra de aluminio = 100 g
temperatura ambiente = 27 ° C
<em>Asumiremos que la barra de aluminio está en equilibrio térmico con el ambiente.
</em>
Esto significa que la temperatura inicial de la barra es de 27 ° C
temperatura final a la que la barra debe calentarse = 60 ° C
el aumento de temperatura ΔT será
ΔT = 60 ° C - 27 ° C = 33 ° C
capacidad calorífica específica c del aluminio = 0.215 cal/g°C
Calor C requerido = mcΔT
<em>C = 100 x 0.215 x 33 = 709.5 cal</em>
Answer:
vi = 2.83 √gR
Explanation:
For this exercise we can use the law of conservation of energy
Let's take a reference system that is at point A, the lowest
Starting point. Lower, point A
Em₀ = Ki = ½ m vi²
Final point. Higher, point B
= K + U
It indicates that at this point the kinetic energy is ki / 2 and the potential energy is ki / 2
K = ki / 2
U = m g (2R)
Energy is conserved so
Em₀ = Em_{f}
½ m vi² = ½ (1/2 m vi²) + m g 2R
½ m vi² (1- ½) = m g 2R
vi² = 4 g 2 R
vi = √ 8gR = 2 √2gR
vi = 2.83 √gR
Answer:
Zero cm and 10 cm......
if my answer helps you than mark me as brainliest
When the Sun's energy moves through space, it reaches Earth's atmosphere and finally the surface. This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet's systems in three ways: by radiation, conduction, and convection.
Explanation:
When a body has an electric charge, it generates an electric field around it, if we introduce an electric charge into this field, it will be affected by the first one. Experiencing a greater force the closer a charge is to the other, that is, depends on the position within the electric field. This force is conservative, so it can be found from the negative derivative of a scalar field, this field is the electric potential energy. Therefore, if the charges are of the same sign, the force will be repulsive (-) and the potential energy will be positive. If the charges are different, the force will be attractive (+) and the potential energy will be negative.
