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earnstyle [38]
3 years ago
11

a rectangle solid has a length of 3cm a height of 4 centimeters and a width of 5cm what is the solid’s volume?

Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

Explanation:

volume = 60cm^3

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Group VII corresponds to the...
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Halogens family

Explanation:

Be familiar with the periodic table

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A large, semi-truck hauling a full load and a small car are traveling in the same direction. As they approach a sharp curve in t
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The semi will have the hardest time changing direction because of its mass. The more mass there is, the more effort it takes to accelerate and decelerate as well as change direction.
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(HELP FAST)Which of the following always changes when a substance undergoes a<br> chemical change?
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A sample of O2 with an initial temperature of 50.0 oC and a volume of 105 L is cooled to -25 oC. The new pressure is 105.4 kPa a
Damm [24]

Answer:

71.92 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

T1 = 50°C = 50 + 273 = 323K

V1 = 105L

T2 = -25°C = -25 + 273 = 248K

P2 = 105.4 kPa

P1 = ?

V2 = 55.0 L

Using P1V1/T1 = P2V2/T2

P1 × 105/323 = 105.4 × 55/248

105P1/323 = 5797/248

0.325P1 = 23.375

P1 = 23.375 ÷ 0.325

P1 = 71.92 kPa

4 0
3 years ago
The combustion of how many moles of ethane (C2H6) would be required to heat 851 g of water from 25.0°C to 98.0°C? (Assume liquid
Debora [2.8K]

Answer : The number of moles of ethane required will be 0.166 mole.

Explanation :

First we have to calculate the heat absorbed by water.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

m = mass of water = 851 g

c = specific heat of water = 4.18J/g^oC

T_{final} = final temperature = 98.0^oC

T_{initial} = initial temperature = 25.0^oC

Now put all the given values in the above formula, we get:

q=851g\times 4.18J/g^oC\times (98.0-25.0)^oC

q=259674.14J=259.67kJ         (1 kJ = 1000 J)

Now we have to calculate the moles of ethane required.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of ethane = 1560.7 kJ/mol (standard value)

q = heat absorbed = 259.67 kJ

n = number of moles of ethane = ?

1560.7kJ/mol=\frac{259.67kJ}{n}

n=\frac{259.67kJ}{1560.7kJ/mol}

n=0.166mole

Therefore, the number of moles of ethane required will be 0.166 mole.

8 0
3 years ago
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