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s2008m [1.1K]
2 years ago
10

А gas has a volume of 100 mL at a temperature of 27°C. At constant pressure,

Chemistry
1 answer:
Colt1911 [192]2 years ago
6 0

Answer:

the volume will either stay the same or double

Explanation:

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How manu moles of N in 0.173g of N2O
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N2O = 28 + 16 = 44g

number of moles

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7 0
3 years ago
A 0.870 g sample of a monoprotic acid is dissolved in water and titrated with 0.300 M KOH.
Vedmedyk [2.9K]

<u>Answer:</u> The molar mass of monoprotic acid is 126.1 g/mol

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of KOH solution = 0.300 M

Volume of solution = 23.00 mL

Putting values in above equation, we get:

0.300M=\frac{\text{Moles of KOH}\times 1000}{23.00}\\\\\text{Moles of KOH}=\frac{0.300\times 23.00}{1000}=0.0069moles

The chemical equation for the reaction of monoprotic acid and KOH follows:

HA+KOH\rightarrow KA+H_2O

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of HA

So, 0.0069 moles of KOH will react with = \frac{1}{1}\times 0.0069=0.0069 moles of HA

To calculate the molar mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of HA = 0.870 g

Moles of monoprotic acid = 0.0069 mol

Putting values in above equation, we get:

0.0069mol=\frac{0.870g}{\text{Molar mass of monoprotic acid}}\\\\\text{Molar mass of monoprotic acid}=\frac{0.870g}{0.0069mol}=126.1g/mol

Hence, the molar mass of monoprotic acid is 126.1 g/mol

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