The values of f(x)[B] and f(x)[C] are {sin²(x) + sin(x)cos(x), sin(x)cos(x)} and {sin(x)cos(x) − sin²(x), sin²(x) + sin(x)cos(x)}, respectively
<h3>How to evaluate the products?</h3>
The trigonometry functions are given as:
f(x) = sin(x)
B = {sin(x) + cos(x), cos(x)}
C = {cos(x) − sin(x), sin(x) + cos(x)}
The product f(x)[B] is:
f(x)[B] = f(x) * B
So, we have:
f(x)[B] = sin(x) * {sin(x) + cos(x), cos(x)}
Evaluate the product
f(x)[B] = {sin²(x) + sin(x)cos(x), sin(x)cos(x)}
The product f(x)[C] is:
f(x)[C] = f(x) * C
So, we have:
f(x)[C] = sin(x) * {cos(x) − sin(x), sin(x) + cos(x)}
Evaluate the product
f(x)[C] = {sin(x)cos(x) − sin²(x), sin²(x) + sin(x)cos(x)}
Hence, the values of f(x)[B] and f(x)[C] are {sin²(x) + sin(x)cos(x), sin(x)cos(x)} and {sin(x)cos(x) − sin²(x), sin²(x) + sin(x)cos(x)}, respectively
Read more about trigonometry ratios at:
brainly.com/question/11967894
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