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4 years ago

RECT is a rectangle. Find x.

Mathematics

2 answers:

Tasya [4]4 years ago

7 0

Where’s the problem ?

Annette [7]4 years ago

3 0

That’s a spam don’t do it

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Please help stuck on geometry test!!!

yaroslaw [1]

Answer:

it will be the second answer

Step-by-step explanation:

if 2 and 6 are the same, that make the opposing angle of the angles 2 and 6 the same which makes the other angles same which make the two lines parallel

4 0

3 years ago

A teacher surveyed her class after they had taken a vocabulary test. Eighteen of the students claimed they had studied

maks197457 [2]

Answer:

C and E are correct

Step-by-step explanation:

We have to calculate mean , median and mode for both groups first:

So,

For the group that studied:

Mean = 92.61

Median=93.5

Mode = 100

For the group that didn't studied:

Mean = 76

Median = 79.5

Mode = No Mode

So,

For statement A:

the difference between means is: 92.61-76=16.61

So the statement is incorrect.

B: There is no mode of the group that studied.

This is not true as the group has a mode of 100

C.The median of the group that did not study is less than 80.

This is true as the median of the group that didn't study is 79.5.

D. The median of the group that studied is over 95

False as the median is less than 95.

E. In general, those students that studied scored much higher than those students that did not study.

As the mean of the group that studied is much more than the group that didn't study so the statement is true ..

6 0

3 years ago

Evaluate -4/(4)2??????????!!!!!!!!!!

scoray [572]

Answer:

-4/2 is equal to -2.

-2 times -4 is equal to 8.

Therefore, (-4)-4/2

5 0

4 years ago

Read 2 more answers

A figure is broken into a rectangle and a triangle. The triangle has a base of 2 and two-thirds feet and height of 3 feet. The r

ohaa [14]

Answer:

$b=2\frac23\:\sf ft$

Area of triangle = 4 ft²

Area of rectangle = $6\frac23\: \sf ft^2$

Area of irregular figure = $10\frac23\: \sf ft^2$

Step-by-step explanation:

$\begin{aligned}\sf Base\:of\:triangle\:(b) & = 5-2\frac13\\\\& = \dfrac{15}{3}-\dfrac73\\\\ & = \dfrac83\\\\ & = 2\frac23\:\sf ft \end{aligned}$

$\begin{aligned}\sf Area\:of\:a\:triangle & =\dfrac12 \sf \times base \times height\\\\& = \dfrac12 \times b \times 3\\\\ & = \dfrac12 \times \dfrac83 \times \dfrac31\\\\ & = \dfrac{24}{6}\\\\ & = 4\: \sf ft^2\end{aligned}$

$\begin{aligned}\sf Area\:of\:rectangle& =\sf length \times width\\\\& = 5 \times 1\frac13\\\\ & = \dfrac51\times \dfrac43\\\\& = \dfrac{20}{3}\\\\ & = 6\frac23\: \sf ft^2\end{aligned}$

$\begin{aligned} \sf Area\:of\:irregular\:figure & = \sf area\:of\:triangle+area\:of\:rectangle\\\\ & = 4 + 6\frac23\\\\ & = 10\frac23\: \sf ft^2\end{aligned}$

5 0

2 years ago

Read 2 more answers

The following questions refer to the CRT Technologies project selection example presented in this chapter. Formulate a constrain

nikklg [1K]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

7 0

4 years ago