Question

A brittle intermetallics specimen is tested with a bending test. The specimen's width 0.45 in and thickness 0.20 in. The length of the specimen between supports 2.5 in. Determine the transverse rupture strength if failure occurs at a load 1200 lb.

Answer 1

Answer:

250 kpsi

Explanation:

Given:

Width of the specimen, w = 0.45 in

Thickness of the specimen, t = 0.20 in

length of the specimen between supports, L = 2.5 in

Failure load, F = 1200 lb

Now,

The transverse rupture strength $\sigma_t=\frac{1.5FL}{wt^2}$

on substituting the respective values, we get

$\sigma_t=\frac{1.5\times1200\times2.5}{0.45\times0.2^2}$

or

$\sigma_t=250,000\ psi\ =\ 250 kpsi$