Answer:
The service level for each component must be 97.91%
Explanation:
If we want a 90% confidence of starting on time, that means we need
As the probability of each component being ready is independent from the others, that means that the probability of the 5 components being ready is equal to multiply each probability:
The probability of being ready on time is equal to the service level (in fraction), and all 5 are equal so we can say:
![0.9=(\mbox{service level(in fraction)})^5\\\\\sqrt[5]{0.9} =\mbox{service level(in fraction)}=0.9791\\\mbox{In percentage}: \mbox{service level (in fraction)}*100 = 97.91\%](https://tex.z-dn.net/?f=0.9%3D%28%5Cmbox%7Bservice%20level%28in%20fraction%29%7D%29%5E5%5C%5C%5C%5C%5Csqrt%5B5%5D%7B0.9%7D%20%3D%5Cmbox%7Bservice%20level%28in%20fraction%29%7D%3D0.9791%5C%5C%5Cmbox%7BIn%20percentage%7D%3A%20%5Cmbox%7Bservice%20level%20%28in%20fraction%29%7D%2A100%20%3D%2097.91%5C%25)
Answer: required tensile stress is 0.889 MPa
Explanation:
Given that;
tensile load is oriented along the [1 1 1] direction
shear stress is 0.242 MPa along [1 0 1] in the (1 1 -1) plane
first we determine
λ which is Angle between [1 1 1] and [1 0 1]
so
cosλ = [ 1(1) + 1(0) + 1(1) ] / [ √(1² + 1² + 1²) √(1² + 0² + 1²)]
= 2 / √3√2 = 2/√6
Next, we determine ∅ which is angle between [1 1 1] and [1 1 -1]
so,
cos∅ = [ 1(1) + 1(1) + 1(-1) ] / [ √(1² + 1² + 1²) √(1² + 1² + (-1)²)]
cos∅ = [ 2-1] / [√3√3 ]
cos∅ = 1/3
Now, we know that;
σ = T_stress/cosλcosθ
so we substitute
σ = 0.242 / ( 2/√6 × 1/3 )
σ = 0.242 / 0.2721
σ = 0.889 MPa
Therefore, required tensile stress is 0.889 MPa
Answer:
Internet of things
Explanation:
This is a good example where the application of technology results are applied to human made things.
Internet of things (IOT), involves the application of one technology results–the internet, embedded into devices such as refrigerator, television etc so as to send and receive data (digital instructions). Such applications of technology results has revolutionized the way we use "human made things".
