Answer:
See below
Step-by-step explanation:
In #4, the angles are vertical because the angles are congruent to each other. Therefore, you would set up the equation x+8=120 where x=112.
In #5, the angles are complementary because their sum is 90°. Therefore, you would set up the equation 43+x+3=90 where x=44.
In #6, the angles are supplementary because their sum is 180°. Therefore, you would set up the equation 76+2x+4=180 where x=50.
Answer:
just google it dude
Step-by-step explanation:
google :)
Answer:
Area of semicircle = 226.08 in²
Step-by-step explanation:
Diameter of semicircle = 24 in
We need to find area of semicircle.
The formula used to find area of semicircle is: 
First we will find radius
We know that: radius = diameter/2 = 24/2 = 12
Now, finding area

So, Area of semicircle = 226.08 in²
Subtract m + ? from m:
11-7 = 4
12-8 - 4
16-12 = 4
21-17 - 4
All the differences are identical, so the rule is to add 4 to m.
The expression would be m + 4
The length of the line segment SR is 15 units.
<h3>How to find the length of a line segment?</h3>
In Δ SRQ as seen in the attached image, we see that;
∠SRQ is a right angle
SQ is the hypotenuse
RT ⊥ SQ
Thus, by triangular rules, we know that;
(RQ)² = TQ × SQ
RQ = 20 units and TQ = 16 units
Thus;
(20)² = 16 × SQ
400 = 16 × SQ
SQ = 400/16
SQ = 25 units
By using Pythagoras theorem in Δ SRQ, we have;
(SR)² + (RQ)² = (SQ)²
RQ = 20 units and SQ = 25 units
Thus;
(SR)² + (20)² = (25)²
(SR)² + 400 = 625
(SR)² = 225
SR = √225
SR = 15 units
The length of the line segment SR is 15 units.
Read more about Length of Line Segment at; brainly.com/question/2437195
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