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3 years ago

What happens to the particles in a substance when temperature rises

Physics

1 answer:

kolbaska11 [484]3 years ago

7 0

Answer:

They gain kinetic energy

Explanation:

When the temperature of the particles in a substance rise, its internal energy increases. This internal energy is thus translated to kinetic energy of the particles in the substance. If the substance is a solid, as the kinetic energy increases, the vibrations of the particles of the substance increases causing it to undergo a change of state to liquid when the temperature reaches its melting point.

This change of state also occurs from the liquid state to the gaseous state as the internal energy of the substance, and thus the kinetic energy of the particles increase when the temperature reaches the substance's boiling point.

So, as the temperature of a substance rises, the particles of the substance gain kinetic energy.

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When do both hemispheres receive the same amount of the sun's energy?

Rasek [7]

Answer:

Both hemispheres receive the same amount of sunlight during both autumnal equinox and vernal equinox 

Explanation:

The vernal or spring equinox happens around March 20 or thereabouts yearly. Equinoxes and various seasons happen as the Earth orbits the Sun and the Earth's orbit. Thus, we have Autumn equinox and spring or vernal equinox. During the Northern hemisphere spring and summer, the northern hemisphere is tilted towards the sun while during the Autumn and winter the northern hemisphere is tilted away from the sun.

During the autumn and spring equinoxes, the earth is neither tilted away or towards the sun. This means that both northern and southern hemisphere receive equal sunlight during these periods: that is hours of daylight and night are roughly about the same.

8 0

3 years ago

The ramp on the back of a moving van is in example of what type simple machine

abruzzese [7]

Inclined Plane.Because an inclined plane is a flat,sloped surface. And a ramp is a perfect example of an inclined plane.

4 0

3 years ago

Read 2 more answers

How did foucaults pendulum and coriolis effect are used to demonstrate earths tilt?

HACTEHA [7]

They do not demonstrate Earth's tilt. In fact, they're not "used" to demonstrate anything. It works the other way:. When you observe the Coriolis effect and the behavior of the Foucault pendulum, and you try to explain why the behave the way they do, one possible simple explanation for both of them is the Earth's ROTATION. Then, when you also observe the rising and setting of the sun and moon, and you also notice how the NUMBERS all go together, the case for the rotating, spherical Earth gets stronger and stronger.

7 0

4 years ago

Starting from zero, an electric current is established in a circuit made of a battery of emf E, a resistor of resistance R and a

igor_vitrenko [27]

Answer:

time constant will decrease and steady state current will decrease on increasing the resistance

Explanation:

As we know that the EMF of cell is E which is used to connected across a resistor and an inductor.

So we will have

$E - iR - L\frac{di}{dt} = 0$

here we know that

$i = \frac{E}{R}(1 - e^{-Rt/L})$

now here we have

$\tau = \frac{L}{R}$

so if we increase the value of resistance of the wire then the time constant will decrease

and hence it will take less time to reach near the steady state value

also the steady state current will be smaller in that case

8 0

3 years ago

A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as t

salantis [7]

Answer:

2.07

Explanation:

Since you didn't supply the drawing, here is what I assumed:

A is the corner opposite the axis of rotation

B is one of the remaining two corners

L1 is the side between A & B

Centripetal acceleration is given by:

ac = v^2 / r = (v / r) * (v / r) * r…………1

Also angular speed is

w = v / r,………….2

Substituting (2) in (1) gives:

ac = (v / r) * (v / r) * r……….3

= (v / r)^2 * r

= w^2 * r

Therefore, the angular acceleration at A and at B are given by:

acA = w^2 * rA……..4

acB = w^2 * rB……..5

It is given that:

acA = n * acB…………6

Substituting (4) and (5) into (6) gives:

w^2 * rA = n * w^2 * rB ……….7==>

rA = n * rB……..8

In terms of the sides L1 and L2:

rA = sqrt (L1^2 + L2^2)…….9

and

rB = L2…………10

Considering (8):

n * L2 = sqrt (L1^2 + L2^2)………11

Squaring both sides:

n^2 * L2^2 = L1^2 + L2^2……….12

Dividing by L2^2:

n^2 = L1^2 / L2^2 + L2^2 / L2^2…….13

= (L1 / L2)^2 + 1 ==>

n^2 - 1 = (L1 / L2)^2 ………14==>

L1 / L2 = sqrt (n^2 - 1) ………15

= sqrt (2.30^2 - 1)

= 2.07. . . . . . <<<=== the value of the ratio L1 / L2 when n = 2.30

8 0

3 years ago