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3 years ago

What happens to the particles in a substance when temperature rises

Physics

1 answer:

kolbaska11 [484]3 years ago

7 0

Answer:

They gain kinetic energy

Explanation:

When the temperature of the particles in a substance rise, its internal energy increases. This internal energy is thus translated to kinetic energy of the particles in the substance. If the substance is a solid, as the kinetic energy increases, the vibrations of the particles of the substance increases causing it to undergo a change of state to liquid when the temperature reaches its melting point.

This change of state also occurs from the liquid state to the gaseous state as the internal energy of the substance, and thus the kinetic energy of the particles increase when the temperature reaches the substance's boiling point.

<u>So, as the temperature of a substance rises, the particles of the substance gain kinetic energy.</u>

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Fantom [35]

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3 years ago

Water is boiled at sea level in a coffeemaker equipped with an immersion-type electric heating element. The coffee maker contain

Luden [163]

Answer:

$P=1362\ W$

$t'=251.659\ s$ is time required to heat to boiling point form initial temperature.

Explanation:

Given:

initial temperature of water, $T_i=18^{\circ}C$

time taken to vapourize half a liter of water, $t=18\ min=1080\ s$

desity of water, $\rho=1\ kg.L^{-1}$

So, the givne mass of water, $m=1\ kg$

enthalpy of vaporization of water, $h_{fg}=2256.4\times 10^{-3}\ J.kg^{-1}$

specific heat of water, $c=4180\ J.kg^{-1}.K^{-1}$

Amount of heat required to raise the temperature of given water mass to 100°C:

$Q_s=m.c.\Delta T$

$Q_s=1\times 4180\times (100-18)$

$Q_s=342760\ J$

Now the amount of heat required to vaporize 0.5 kg of water:

$Q_v=m'\times h_{fg}$

where:

$m'=0.5\ kg=$ mass of water vaporized due to boiling

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$Q_v=1.1282\times 10^{6}\ J$

Now the power rating of the boiler:

$P=\frac{Q_s+Q_v}{t}$

$P=\frac{342760+1128200}{1080}$

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3 years ago

A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of th

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Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

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Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

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3 years ago

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Rasek [7]

Answer:

$W=173.48J$

Explanation:

information we know:

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-------------

In this case we need the formulas to calculate the components of the force (because to calculate the work we need the horizontal component of the force).

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