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Aleks [24]
4 years ago
5

Which example possesses mechanical potential energy?. A. a taut guitar string. B. an oscillating pendulum. C. a roller coaster r

ide. D. a child on a swing. E. a speeding car
Physics
2 answers:
Anuta_ua [19.1K]4 years ago
8 0

a taut guitar string

NeTakaya4 years ago
7 0
<span>
The taut guitar string haspotencial energy which we can see in action.</span>  <span>· so option a is correct.</span>
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What is the electric force acting between two charges of 0.0072 C and -0.0060 C that are 0.0040 m apart?
telo118 [61]
Answer:
F = -2.4 * 10¹⁰ N

Explanation:
To get the electric force between two charges, we would use Coulomb's law which states that:
F = \frac{k * q1 * q2}{d^{2} }

where:
F is the force between the two charges
k is Coulomb's constant = 9 * 10⁹ Nm²/C²
q1 is the first charge = 0.0072 C
q2 is the second charge = -0.006 C
d is the distance between the two charges = 0.004 m

Substitute with the givens in the above formula to get the force between the two charges as follows:
F = \frac{9*10^9*0.0072*-0.006}{(0.004)^2}

F = -2.4 * 10¹⁰ N

Hope this helps :)
8 0
3 years ago
Some of the energy the car gained as it was pulled was lost because of heat from friction. The rest of the energy was transforme
Lisa [10]

Answer:

454,320 joules

Explanation:

The work done on an object is equal to its change in kinetic energy: Change in KE = F × d.

Plug the values for F and d into the formula and solve:

Change in KE = 2,524 × 180

= 454,320 joules

The roller coaster gains 454,320 joules of energy from the work done on it by the chain.

7 0
4 years ago
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The magnetosphere protects Earth from _____. a.solar radiation b. the solar wind c. the cold of space d.asteroid hits e.gamma ra
aivan3 [116]
Solar Radiation, The Solar Wind, and Gamma Ray Bursts
4 0
3 years ago
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What is the magnitude of fs on an object lying on a flat surface without moving, on
Degger [83]

The magnitude of the force acting on the object lying on a flat surface without moving is 10 N.

The given parameters;

  • magnitude of force on the object, F = 10 N
  • angle between the object and the horizontal flat surface = 0⁰

Apply Newton's second law of motion to determine the magnitude of the force on the object.

Due to the position of the object, the magnitude of the force acting on it is calculated as;

\Sigma F_{net} = F\sin(\theta ) + F cos(\theta)\\\\\Sigma F_{net} = 10 sin(0) + 10cos(0)\\\\\Sigma F_{net} = 10 \ N

Therefore, the magnitude of the force acting on the object is 10 N.

Learn more here: brainly.com/question/19887955

7 0
3 years ago
Please help me on this position-time graph assignment!!!
saw5 [17]

\text{Hello there! :)}

\text{The velocity is essentially the slope of the graph in a position vs. time graph, so:}

\text{Given: From 0 - 8 sec, velocity of 10 m/s.}\\\\\text{From 8 - 18 sec, velocity of -5 m/s. (In opposite direction because of the negative sign)}\\\\\\\text{From 18 - 22 sec, velocity of 0 m/s. (Object at rest)}\\\\\text{From 22 - 24 sec, velocity of 5 m/s.}\\\\\text{Graph the position vs. time graph using the velocities as the slope of the line }

6 0
4 years ago
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