Answer:
The answer is below!!
Explanation:
Electromagnetic radiation (e.g., radio, microwaves, light) can be modeled as a wave of changing electric and magnetic fields or as particles called photons. The wave model is useful for explaining many features of electro-magnetic radiation, and the particle model explains other features.
Hope I Helped!!
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Well for you to get 980 Hz you divided 344 m/s with .35 m
Answer:
the high temperature needed to operate this refrigerator is C) 137.4° C
Explanation:
Hello!
The carnot refrigeration cycle is one in which a machine absorbs heat from an enclosure and expels it to the surroundings, the equation that defines the COP performance coefficient for this cycle is:
![COP=\frac{T1}{T2-T1}](https://tex.z-dn.net/?f=COP%3D%5Cfrac%7BT1%7D%7BT2-T1%7D)
COP=performance coefficient =2.1
T1= Low temperature
T2=high temperature
Now use algebra to find the high temperature
![COP=\frac{T1}{T2-T1}\\(T2-T1)=\frac{T1}{COP}\\T2=\frac{T1}{COP}+T1\\T2=T1(\frac{1}{COP} +1)](https://tex.z-dn.net/?f=COP%3D%5Cfrac%7BT1%7D%7BT2-T1%7D%5C%5C%28T2-T1%29%3D%5Cfrac%7BT1%7D%7BCOP%7D%5C%5CT2%3D%5Cfrac%7BT1%7D%7BCOP%7D%2BT1%5C%5CT2%3DT1%28%5Cfrac%7B1%7D%7BCOP%7D%20%2B1%29)
If we replace the values:
note = remember that the temperature must be in absolute units, for which we must add 273.15 to the low temperature to find the temperature in Kelvin
T1 = 5 + 273.15 = 278.15K
![T2=278.15(\frac{1}{2.1} +1)=410.60k](https://tex.z-dn.net/?f=T2%3D278.15%28%5Cfrac%7B1%7D%7B2.1%7D%20%2B1%29%3D410.60k)
In celsius
T2=410.60-273.15=137.4° C
the high temperature needed to operate this refrigerator is C) 137.4° C
KE = 1/2 * m * v2
We have to rearrange this so the subject is mass. (because the question asks for the mass of the object) :
Mass = (2 * KE) / v
Now input the values into this equation to get your answer :
Mass = (2 * KE) / v
Mass = (2 * 480) / 8
Mass = 960 / 8
Mass = 120
Answer:
a
![v = 5.39 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%20%205.39%20%5C%20%20m%2Fs)
b
Horizontal component
vertical component
![v_y = - 2.0 \ m/s](https://tex.z-dn.net/?f=v_y%20%20%3D%20%20-%202.0%20%5C%20%20m%2Fs)
c
![t = 0.921 \ s](https://tex.z-dn.net/?f=t%20%3D%20%200.921%20%5C%20%20s)
d
![d = 4.605 \ m](https://tex.z-dn.net/?f=d%20%3D%204.605%20%5C%20%20m%20)
Explanation:
Generally from the question we can deduce that he initial velocity of the cork, as seen by an observer on the ground in terms of the x unit vector is
due to the fact that the cork is moving horizontally
Generally from the question we can deduce that the vertical and horizontal components of the initial velocity is
due to the fact that the balloon is moving downward which is the negative which will also cause the cork to move vertically with the balloon speed
Generally the initial velocity (magnitude and direction) of the cork, as seen by an observer on the ground is mathematically represented as
![v = \sqrt{ v^2 _x + v^2 _y }](https://tex.z-dn.net/?f=v%20%20%3D%20%20%5Csqrt%7B%20v%5E2%20_x%20%20%2B%20v%5E2%20_y%20%20%7D)
![v = \sqrt{ 5^2 + (-2)^2 _y }](https://tex.z-dn.net/?f=v%20%20%3D%20%20%5Csqrt%7B%205%5E2%20%20%2B%20%28-2%29%5E2%20_y%20%20%7D)
![v = 5.39 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%20%205.39%20%5C%20%20m%2Fs)
Generally the initial direction of motion as seen by the same observer is mathematically represented as
![\theta = tan^{-1}[\frac{2}{5} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7B2%7D%7B5%7D%20%5D)
![\theta = 21.80^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%2021.80%5Eo)
Generally the time taken by the cork in the air before landing is mathematically represented as
![D = ut + \frac{1}{2} g t^2](https://tex.z-dn.net/?f=D%20%20%3D%20%20ut%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20g%20t%5E2)
So D = 6 \ m from the question
g = 9.8 \ m/s^2
u =
= 2 m/s this because we are considering the vertical motion
So
![6 = 2 t + \frac{1}{2} * 9.8* t^2](https://tex.z-dn.net/?f=6%20%20%3D%20%20%202%20t%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%209.8%2A%20%20t%5E2)
![6 = 2 t + 4.9 t^2](https://tex.z-dn.net/?f=6%20%20%3D%20%20%202%20t%20%20%2B%204.9%20%20t%5E2)
Solving using quadratic formula w have that
![t = 0.921 \ s](https://tex.z-dn.net/?f=t%20%3D%20%200.921%20%5C%20%20s)
Generally the distance of the cork from the balloon is mathematically represented as
![d = v_x * t](https://tex.z-dn.net/?f=d%20%3D%20v_x%20%20%2A%20%20t)
![d = 5 * 0.921](https://tex.z-dn.net/?f=d%20%3D%205%20%20%2A%200.921%20)
![d = 4.605 \ m](https://tex.z-dn.net/?f=d%20%3D%204.605%20%5C%20%20m%20)