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Nonamiya [84]
3 years ago
7

Plz help with this paper.

Physics
1 answer:
lord [1]3 years ago
4 0

Answer:

1. a) Draw a line towards the right side from the engine

b) This force pushes the boat forward and helps it accelerate further

2. a) Fixed volume for both solid and liquid

Compressible for only solid

Fixed shape is also for only Solid

b) The answer is 'c'

c) Solids, because they have their particles closely packed therefore they can be compressed (not so sure bout this answer)

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A sliver cylindrical rod has a length of 0.5 m and a radius of 0.4 m, find the density of the rod if it's mass is 2.640 kg
Serga [27]

Answer:

Density=10.50kg/m³

Explanation:

Solution,\\Height(h)=0.5m\\Radius(r)=0.4m\\Now, \\Volume=\pi r^{2} h\\\\Volume=\pi *(0.4m)^{2} *0.5m\\\\Volume=0.251327m^{3} \\\\Again,\\\\Density=\frac{mass}{volume} \\\\Density=\frac{2.640kg}{0.251327} \\\\Density=10.50kg/m^{3}

7 0
2 years ago
Which of these processes in the water cycle occur at a very high rate, to cause a hurricane?
Pavel [41]
Answer: d. evaporation and condensation

Water vapor is known as the main fuel that moves the hurricane. The evaporation will cause the water vapor to move upward carrying the latent heat of condensation. The vapor will cause condensation later. If both happen at a very high rate, the wind produced can become a hurricane. 
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4 years ago
Which state of matter has atoms that are spread out and bouncy?
NikAS [45]
The stage where atoms are spread out and bouncy is the gas stage.

7 0
3 years ago
Anyone going to be my friend
Artemon [7]

Explanation:

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5 0
3 years ago
Electrical systems are governed by Ohm’s law, which states that V = IR, where V is the voltage, I is the current, and R is the r
ella [17]

Answer:

\frac{dR(t)}{dt}=0.06\Omega

Explanation:

Since R(t)=\frac{V}{I(t)}, we calculate the resistance rate by deriving this formula with respect to time:

\frac{dR(t)}{dt}=\frac{d}{dt}(\frac{V}{I(t)})=V\frac{d}{dt}(\frac{1}{I(t)})

Deriving what is left (remember that (\frac{1}{f(x)})'=-\frac{1}{f(x)^2}f'(x)):

\frac{d}{dt}(\frac{1}{I(t)})=-\frac{1}{I(t)^2}\frac{dI(t)}{dt}

So we have:

\frac{dR(t)}{dt}=-\frac{V}{I(t)^2}\frac{dI(t)}{dt}

Which for our values is (the rate of <em>I(t)</em> is decreasing so we put a negative sign):

\frac{dR(t)}{dt}=-\frac{24V}{(56A)^2}(-8A/s)=0.06\Omega

8 0
3 years ago
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