Question

The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a size aa battery that supplies a constant voltage of 1.5 volts. What voltage would be measured across the secondary coil?

Answer 1

Answer:

3 volts

Explanation:

Number of turns in primary coil = $N_{p}$ = 100

Number of turns in secondary coil = $N_{s}$ = 200

Voltage across primary coil = $V_{p}$ = 1.5 volts

Voltage across secondary coil = $V_{s}$ = ?

In a transformer, the ratio of number of turns of primary to secondary coil is equal to the ratio of the respective voltages i.e.

$\frac{N_{p} }{N_{s} } =\frac{V_{p} }{V_{s} }$

Using the given values, we get:

$\frac{100}{200}=\frac{1.5}{V_{s} }\\V_{s}=1.5 \times \frac{200}{100}\\V_{s}=3$

Thus, the voltage measure across secondary coil would be 3 volts