The 60 kg man in the bosun's chair exerts a pull of 363 n on the rope for a short interval. Find his acceleration in m/s2. Negle

Question

2 years ago

15

ct the mass of the chair, rope, and pulleys. Use upwards as positive

1 answer:

LUCKY_DIMON [66] · Answer 1 · 2023-04-28T13:13:19+03:00

The acceleration when a 60 kg man in bosun's chair exerts a pull, is -3.76 m/s².

<h3>What is acceleration?</h3>

The acceleration is the time rate of change of velocity.

Given the mass of man m= 60 kg and pull = 363N

According to the equilibrium conditions, 3T -mg =ma

The pull is equal to the tension 3T =363 N

Substituting the values, we get

363N - 60x 9.81 = 60a

a =-3.76m/s²

Thus, the acceleration is -3.76m/s².

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