The number of moles of hydrogen required will be 20 moles.
<h3>Stoichiometric mole ratio</h3>
First, let us look at the balanced equation of the reaction:
From the above equation, it is obvious that 1 mole of carbon requires 2 moles of hydrogen in order to produce a mole of methane.
In other words, the mole ratio of hydrogen to methane is 2:1. For every 1 mole of methane produced, 2 moles of hydrogen are consumed.
Now, what we want to produce is 10 moles of methane. The amount, in moles of hydrogen required, is calculated by:
10 moles x 2 = 20 moles.
Thus, 20 moles of hydrogen would be required to produce 10 moles of methane.
More on stoichiometric mole ratios can be found here: brainly.com/question/15053457
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Answer:
<h3>The answer is 11 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 3025 g
volume = 275 mL
We have
We have the final answer as
<h3>11 g/mL</h3>
Hope this helps you
Answer:
This makes it isoelectronic with krypton. The anion of bromine is Br-. The element rubidium has an electronic number 37. It loses one electron to gain a positive charge and change to Rb+ which has 36 electrons and is a cation that is isoelectronic with krypton
Answer:
1.5055×10²⁴
Explanation:
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Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
