CH2O2 formic acid I believe so
Reduction refers to a chemical reaction in which electrons are gained by one of the atoms involved in the reaction and at the same time lowering of an oxidation state of that atom takes place.
In the given case, the reduction occurs at the cathode. In aqueous, V (vanadium) is present in +5 oxidation state that on reduction modifies to vanadium (aq) with +1 oxidation state.
The half reaction is:
V⁵⁺ (aq) + 4e⁻ → V¹⁺ (aq)
Answer:
Answer is Object 2 (which has a density of 1.9 g/cm³).
Explanation;
When object is floating, the weight of that object is less than the up thrust on it.
When an object fully submerged and floating, then the weight of that object is equal to the up thrust on it.
This is known as the Archemide's principle.
Both up thrust and weight depends on the density. Hence, if the density of the solution is high, then the up thrust also high. If the density high, the the weight of the object also high.
Hence, to sink the object in water, that object should be denser than water. Hence, answer is object 3 which has a higher density than water.
Explanation:
From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 grams
mass of oxygen = 16 grams
molar mass of surcose = 12(12) + 22(1) + 11(16) = 342 grams
number of molecules = number of moles x Avogadro's number
number of moles = number of molecules / Avogadro's number
number of moles = (2.2x10^17) / (6.02x10^23) = 3.6544 x 10^-7 moles
number of moles = mass / molar mass
mass = number of moles x molar mass
mass = 3.6544 x 10^-7 x 342 = 1.249 x 10^-4 grams = 0.12498 mg
