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Radda [10]
2 years ago
11

the process of making alloys involves _____ pure metals to remove impurities. Then the pure metals are ____ with other component

s
Physics
2 answers:
Law Incorporation [45]2 years ago
5 0
I think this is the answer for the first line(Cooling ,Heating or mixing ) and for the second line is(broken down,cooled,mixed)
vitfil [10]2 years ago
5 0

The process of making alloys involves ( Heating ) pure metals to remove impurities. Then the pure metals are(mixed) with other components. An alloy is a mixture of metals or a mixture of a metal and another element. Alloys are defined by a metallic bonding character.

Explanation:

The preponderance of alloys are produced by combining metals in the molten state; then the mixture is poured into metal or sand molds and delivered to harden. Usually, the major ingredient vanishes first; then the others are assigned to it and should presently dissolve.

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3 years ago
In a region of space where gravitational forces can be neglected, a sphere is accelerated by a uniform light beam of intensity 8
BlackZzzverrR [31]

Answer:

The correct answer is B

Explanation:

To calculate the acceleration we must use Newton's second law

      F = m a

      a = F / m

To calculate the force we use the defined pressure and the radiation pressure for an absorbent surface

       P = I / c        absorbent surface

       P = F / A

       F / A = I / c

       F = I A / c

The area of ​​area of ​​a circle is

      A = π r²

We replace

     F = I π r² / c

Let's calculate

     F = 8.0 10⁻³ π (1.0 10⁻⁶)²/3 10⁸

     F = 8.375 10⁻²³ N

Density is

      ρ = m / V

      m = ρ V

      m = ρ (4/3 π r³)

      m = 4500 (4/3 π (1 10⁻⁶)³)

      m = 1,885 10⁻¹⁴ kg

Let's calculate the acceleration

     a = 8.375 10⁻²³ / 1.885 10⁻¹⁴

     a = 4.44 10⁻⁹ m/s²               absorbent surface

The correct answer is B

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3 years ago
What is the sidereal period used in Kepler’s third law?
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8 0
2 years ago
Read 2 more answers
A double slit that is illuminated with coherent light of wavelength 644 nm produces a pattern of bright and dark fringes on a sc
shutvik [7]

Answer:

2.77 cm

Explanation:

d = separation between the slits = 2783 x 10⁻⁹ m

\lambda = wavelength of coherent light = 644 nm = 644 x 10⁻⁹ m

D = Distance of the screen = 6 cm = 0.06 m

y_{n} = Position of nth bright fringe

Position of nth bright fringe is given as

y_{n} = \frac{nD\lambda }{d}  

for n = 2

y_{2} = \frac{nD\lambda }{d}  

y_{2} = \frac{(2)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}

y_{2} = 0.0278 m

for n = 4

y_{4} = \frac{nD\lambda }{d}  

y_{4} = \frac{(4)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}

y_{4} = 0.0555 m

Distance between 4th and 2nd bright fringes is given as

w = y_{4} - y_{2} = 0.0555 - 0.0278 = 0.0277 m

w = 2.77 cm

8 0
3 years ago
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