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Andreyy89
3 years ago
6

The flower of the species Rosa verdus can be either green or red. in the species a single gene with two alleles determines flowe

r color. Small g is the recessive allele that results in red flowers in the homozygous condition. Which two genotypes will result in plants with green flowers.
Physics
2 answers:
vladimir2022 [97]3 years ago
6 0

Answer:

SS and Ss

I did the test!!!!

Simora [160]3 years ago
4 0
Since G is a dominate trait the 2 genotypes would be Gg or GG
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The answer is B tell me if I am wrong.
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2 years ago
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When drawing a vector, you should represent the magnitude of the vector by the length of the arrow. A. True O B. False​
bixtya [17]

Answer: A. True

Explanation:

8 0
2 years ago
What is the crucial ingredient for the formation of lightning such that without this ingredient, lightning does not form in a th
Sunny_sXe [5.5K]

Answer:

High Potential Difference

Explanation:

Lightning is a type of Electrical Discharge and for any electrical discharge to happen we require a high potential difference between two areas in space.

In case of lightning this potential difference can be formed between 2 clouds, between a cloud and the ground or two different areas in the same cloud.

So during lightning this potential difference causes different type of lightning due to electrification followed by charge separation and hence aggregation of charge is specific areas of clouds.

8 0
3 years ago
A siphon pumps water from a large reservoir to a lower tank that is initially empty. The tank also has a rounded orifice 20 ft b
trasher [3.6K]

Answer:

height of the water rise in tank is 10ft

Explanation:

Apply the bernoulli's equation between the reservoir surface (1) and siphon exit (2)

\frac{P_1}{pg} + \frac{V^2_1}{2g} + z_1= \frac{P_2}{pg} + \frac{V_2^2}{2g} +z_2

\frac{P_1}{pg} + \frac{V^2_1}{2g} +( z_1-z_2)= \frac{P_2}{pg} + \frac{V_2^2}{2g}-------(1)

substitute P_a_t_m for P_1, (P_a_t_m +pgh) for P_2

0ft/s for V₁, 20ft for (z₁ - z₂) and 32.2ft/s² for g in eqn (1)

\frac{P_1}{pg} + \frac{V^2_1}{2g} +( z_1-z_2)= \frac{P_2}{pg} + \frac{V_2^2}{2g}

\frac{P_1}{pg} + \frac{0^2_1}{2g} +( 20)= \frac{(P_a_t_m+pgh)}{pg} +\frac{V^2_2}{2\times32.2} \\\\V_2 = \sqrt{64.4(20-h)}

Applying bernoulli's equation between tank surface (3) and orifice exit (4)

\frac{P_3}{pg} + \frac{V^2_3}{2g} + z_3= \frac{P_4}{pg} + \frac{V_4^2}{2g} +z_4

substitute

P_a_t_m for P_3, P_a_t_m for P_4

0ft/s for V₃, h for z₃, 0ft for z₄, 32,2ft/s² for g

\frac{P_a_t_m}{pg} + \frac{0^2}{2g} +h=\frac{P_a_t_m}{pg} + \frac{V_4^2}{2\times32.2} +0\\\\V_4 =\sqrt{64.4h}

At equillibrium Fow rate at point 2 is equal to flow rate at point 4

Q₂ = Q₄

A₂V₂ = A₃V₃

The diameter of the orifice and the siphon are equal , hence there area should be the same

substitute A₂ for A₃

\sqrt{64.4(20-h)} for V₂

\sqrt{64.4h} for V₄

A₂V₂ = A₃V₃

A_2\sqrt{64.4(20-h)} = A_2\sqrt{64.4h}\\\\20-h=h\\\\h= 10ft

Therefore ,height of the water rise in tank is 10ft

3 0
3 years ago
A liquid has a density that varies with depth h, such that ρ=(0.001h+1.60)slug/ft3, where h is in feet.
Valentin [98]

We need to find pressure when h = 85 ft

We know the formula for pressure P = hρg, where h is the height of liquid, ρ is the density of liquid and g is the acceleration due to gravity value.

We have ρ = (0.001h+1.60)slug/ft^3 = 515.24 kg/m^3

                h = 25.908 m

                g = 9.8m/s^2

  So pressure, P = 25.908*515.24*9.8 = 13088.61 N/m^2

                             = 18.97 psi

5 0
3 years ago
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