Answer:
See below
Explanation:
Vertical position = 45 +  20 sin (30) t  - 4.9 t^2 
  when it hits ground this = 0
                0 = -4.9t^2 + 20 sin (30 ) t + 45 
                 0 = -4.9t^2 + 10 t +45 = 0     solve for t =4.22 sec
   max height is at  t= - b/2a = 10/9.8 =1.02
      use this value of 't' in the equation to calculate max height = 50.1 m
       it has  4.22 - 1.02 to free fall = 3.2 seconds free fall 
            v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL
       it will <u>also</u> still have horizontal velocity =  20 cos 30 = 17.32 m/s 
         total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s
Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m