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ahrayia [7]
2 years ago
15

a car with mass 1400kg has a net forward force of 4500N applied to it. the car starts from rest and travels down a horizontal hi

ghway. if travelled 100m what is it velocity​
Physics
1 answer:
belka [17]2 years ago
6 0

Answer:

25.3m/s

Explanation:

F=ma

F is 4500, M is 1400kg, A is ?

4500=1400×a

a=4500/1400

a=3.2m/s²

then equation of motion

V²=U²+2as

V=?,U=0, a=3.2,s=100m

V²=0+2×3.2×100

V²=640

  • square both side

V=√640

V= 25.3m/s

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Answer:

82.1 km

Explanation:

We need to resolve each displacement along two perpendicular directions: the east-west direction (let's label it with x) and the north-south direction (y). Resolving each vector:

A_x = (72) sin 30^{\circ} =36.0 km\\A_y = (72) cos 30^{\circ} = 62.4 km

Vector B is 48 km south, so:

B_x = 0\\B_y = -48

Finally, vector C:

C_x = -(100) cos 30^{\circ} =-86.6 km\\C_y = (100) sin 30^{\circ} = 50.0 km

Now we add the components along each direction:

R_x = A_x + B_x + C_x = 36.0 + 0 +(-86.6)=-50.6 km\\R_y = A_y+B_y+C_y = 62.4+(-48)+50.0=64.6 km

So, the resultant (which is the distance in a straight line between the starting point and the final point of the motion) is

R=\sqrt{R_x^2+R_y^2}=\sqrt{(-50.6)^2+(64.6)^2}=82.1 km

4 0
2 years ago
A large sheet of charge has a uniform charge density of 9  μCm2. What is the electric field due to this charge at a point just
Alex73 [517]

Answer:

Explanation:

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According to the Gauss theorem,

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E = \frac{9\times 10^{-6}}{2\times 8.854\times 10^{-12}}

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A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift fo
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Explanation:

we use Newtons second law

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