1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DanielleElmas [232]
3 years ago
6

Which workout schedule would be BEST suited for a weight-lifting workout that builds both strength and endurance

Physics
2 answers:
Anvisha [2.4K]3 years ago
6 0
On enginuity the answer is C.
VLD [36.1K]3 years ago
4 0
My workout schedule is day on - day off

This helps the body rest after the work out and let it gain/build muscle mass

Good luck
You might be interested in
Tyler is in downtown San Antonio entertaining the tourists with amazing feats of physics. He carries a nickel
professor190 [17]

Answer:

The velocity of the nickel just before it hits the ground is approximately 49.3 m/s

Explanation:

In order to calculate the velocity of the nickel just before it hits the ground, we recall the kinematic equation of motion, v² = u² + 2·g·h, where the variables of the equation are defined as follows;

v = The velocity of the nickel just before it hits the ground after it is pushed off the observation deck

u = The initial velocity of the nickel just before it is pushed off the observation deck = 0 m/s

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which he nickel is pushed off the edge = 124 m

Substituting the given values and the constant, "g", we have;

v² = 0² + 2 × 9.8 × 124 = 2,430.4

v = √2,430.4

Using a graphing calculator, we have;

v = √2,430.4 = 14·√(62/5) ≈ 49.3

The velocity of the nickel just before it hits the ground = v ≈ 49.3 m/s.

3 0
3 years ago
What is the entropy of a closed system in which 28 distinguishable grains of sand are distributed among 1000 distinguishable equ
baherus [9]

Answer:

193.4 J/K

Explanation:

For a closed system, the entropy is given as the natural logarithm of microstates.

The number of particles ( grains of sand ) N = 28

The number of boxes ( compartments ) M = 1000

Entropy is the logarithm of number of microstates

S=ln \psi

But the number of microstates is given by

\psi=M^{N} hence S=ln M^{N}=\ln (1000^{28})= \boxed{193.4 J/K}

4 0
3 years ago
When you look at green dots with a red filter what color did you see?
Dimas [21]
-- Looking at the dots casually, they look green because they absorb all other
colors of light, and only green light is left to proceed to your eyes. (In order for
this to work, there has to be some green in the light shining on the dots.
Daylight and most light bulbs work fine.)

-- The filter looks red because it absorbs all other colors of light, and only
the red light is left to pass through the filter and come out on the other side.

-- When the green light from the dots hits the red filter, it's absorbed in the
filter, and there's no light left to come out on the other side.

If you're looking through the filter at the dots, they look <em>black</em>.

3 0
3 years ago
The Moon has a radius of 1.7 × 106 m and a mass of 7.3 × 1022 kg. Find the gravitational field on the surface of the Moon.
Lisa [10]

Answer:

10.7*10^{6}

Explanation:

6 0
3 years ago
A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow
shusha [124]

Answer:

150000000

\dfrac{F_e}{F_g}=0.00000203873598369

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

1\ C=6.25\times 10^{18}\ electrons

Number electrons is

n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000

The number of electrons added or removed was 150000000

Force is given by

F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N

The ratio is

\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369

The ratio is \dfrac{F_e}{F_g}=0.00000203873598369

Balancing the forces we get

Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C

The electric field required is 49050000 N/C

4 0
3 years ago
Other questions:
  • HELP ASAP PLS! GIVING BRAINLIEST!!
    5·2 answers
  • Advantages of hubble law
    5·1 answer
  • Calculate the force of gravity acting on an object that has a mass of 1.3 kilograms. The object is on Earth soyuz 9.8 m / S 2 fo
    7·1 answer
  • If the rocket burns its fuel in a time of 50.0 s and the relative speed of the exhaust gas is vex = 2100 m/s, what must the mass
    10·1 answer
  • describe at least 2 reasons (pieces of evidence) for why we know that the continents were once joined together and have since dr
    6·2 answers
  • Which statement best describes the difference between how lenses and
    5·2 answers
  • Parallel rays of monochromatic light with wavelength 582 nm illuminate two identical slits and produce an interference pattern o
    8·1 answer
  • Your physics TA has a far point of 0.759 m from her eyes and is able to see distant objects in focus when wearing glasses with a
    9·1 answer
  • Question 3. A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the +z-direction. The a magnetic field is
    10·1 answer
  • At what temperature would volume of gas be doubled of pressure at the same time increase from 700 to 800 mm of Hg? please answer
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!