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DaniilM [7]
3 years ago
9

What would I write in the results, conclusion, and keywords and research components for my 4th grade son's Science Fair Project?

We did the project on the growth of Epsom SALT crystals in 6 different glass jars, all done the same day but 2 in the am, 2 in the afternoon, and last 2 in the evening. They all grew crystals but the ones with the best growth were done at different times one was in the am and other was in afternoon. I'm stumped been done school a long time and very busy single mom of three.
Chemistry
1 answer:
Mrrafil [7]3 years ago
6 0
Just write what you did in your project
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What the volume is.
alekssr [168]

The molar mass of NO₂ is 46.0 g/mol

The molar mass of Pb (NO₃)₂ is 331.2 g/mol

First there is a need to find the number of moles of NO₂ via the stoichiometry of reaction:

2Pb(NO₃)₂ → 2PbO (s) + 4NO₂ (g) + 02 (g)

2 × 331.2 g = 4 × 46.0 g

16.87 g = x (mass of NO₂)

mass of NO₂ = 16.87 × 4 × 46 / 2 × 331.2

mass of NO₂ = 3104.08 / 662.4

mass of NO₂ = 4.686 g of NO₂

Now the number of moles are:

1 mole NO₂ = 46.0 g

x moles of NO₂ = 4.686 g

4.686 × 1 / 46.0 = 0.101 moles of NO₂

1 mole = 22.4 L (at STP)

0.101 moles of NO₂ = 0.101 × 22.4 / 1

= 2.26 L

4 0
3 years ago
What SI Unit would best be used to express the height of your classroom ceiling?
ivolga24 [154]

SI unit of length - meters
3 0
3 years ago
If you combine 290.0 mL 290.0 mL of water at 25.00 ∘ C 25.00 ∘C and 140.0 mL 140.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t
Alexxandr [17]

Answer:

The final temperature is 47.79 °C

Explanation:

Step 1: Data given

Sample 1 has a volume of 290.0 mL

Temperature of sample 1 = 25.00 °C

Sample 2 has a volume of 140.00 mL

Temperature of sample 2 = 95.00 °C

Step 2: Calculate the final temperature

Heat lost = heat gained

Qlost = -Qgained

Q = m*c* ΔT

Q(sample1) = -Q(sample2)

m(sample1) * c(sample1) * ΔT(sample1) = -m(sample2)*c(sample2) *ΔT(sample2)

⇒with m(sample1) = the mass of sample 1 = 290.0 mL * 1g/mL = 290 grams

⇒with c(sample 1) = the specific heat of water = c(sample 2)

⇒with ΔT(sample 1) = the change of temperature = T2 - T1 = T2 - 25.00 °C

⇒with m(sample2) = the mass of sample 2 = 140.0 mL * 1g/mL = 140 grams

⇒with c(sample2) = the specific heat of water = c(sample1)

⇒with ΔT(sample2) = T2 -T1 = T2 - 95.00°C

m(sample1) *  ΔT(sample1) = -m(sample2)*ΔT(sample2)

290 *(T2-25.0) = -140 *(T2 - 95.0)

290 T2 - 7250 = -140 T2 + 13300

430 T2 = 20550

T2 = 47.79 °C

The final temperature is 47.79 °C

4 0
3 years ago
How does the negative control of the lac operon by glucose function through inducer exclusion? See Section 18.3 (Page 373) . Vie
just olya [345]

Answer:

High glucose concentrations prevent the transport of lactose into the cell.

Explanation:

7 0
3 years ago
Name at least 3 ways the Periodic Table is organized. *
Lesechka [4]

Answer:

The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. The rows are called periods.

Explanation: Cause I'm smart like that!

8 0
3 years ago
Read 2 more answers
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