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laila [671]
2 years ago
13

The position of a particle moving in the xy plane is given by the parametric equations x(t)=t^3-3t^2

Physics
1 answer:
Basile [38]2 years ago
4 0

The value of t  for which the particle is at rest is :  t = 2

<u>Given data:</u>

X = t³ - 3t²

Y = 2t³ - 3t² - 12t

<h3>Determine the values of t for which the particle is at rest </h3>

<u>First step : Determine the first derivative of eac equations</u>

dx = 3t² - 6t

dy = 6t² - 6t - 12

<u>Next step : </u><u>determine</u><u> the value of slope ( dy/dx ) = o </u>

dy / dx = ( 6 (t² - t - 2) )  /  ( 3t ( t - 2) )

Therefore

dy / dx = ( 2 ( t + 1 ) (t - 2) ) / ( t ( t -2) )

           = 0

Therefore at ; t = -1 and 2  the particle is at rest

Hence we can conclude that Neglecting the negative value the particle will be at rest when t = 2

Learn more about Object at rest : brainly.com/question/24160573

#SPJ1

<u>Attached below is the complete question</u>

<em>The position of a particle moving in the xy-plane is given by the parametric equations x = t3 - 3t2 and y = 2t3 - 3t2 - 12t. For what values of t is the particle at rest?</em>

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A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast
kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 is the mass of the first mosquito

u_1 = 0 is the initial velocity of the mosquito

m_2 = 50 m_1 is the mass of the raindrop

u_2 = 8.4 m/s is the initial velocity of the raindrop

v is the final combined velocity of the raindrop+mosquito

Re-arranging the equation and substituting, we find:  

m_1 u_1 + 50 m_1 u_2 = (m_1 + 50 m_1) v\\50 m_1 u_2 = 51 m_1 v\\50 u_2 = 51 v\\v=\frac{50}{51}u_2 = \frac{50}{51}(8.4)=8.2 m/s

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4 0
3 years ago
HELPPPPPPP PLEASE! ASAPPPPPP
Sav [38]

Answer:

Answer:

Debt payments to income ratio = 22.74%

Explanation:

Debts payment to Income ratio is calculated as follows:

= \frac{Total\ debt\ payment}{Total\ Income}

Total Income

Total debt payment

We have total debts payment = auto loan payment 685 + student loan payment685+studentloanpayment375 + credit card payment 125 =125=1,185

Total Income = $5,210

Note: Credit card is also a kind of debt as firstly all the expenses are met during the period and then the payment is made at the end of the period, therefore, there is a loan in the period. Therefore, it will be considered for payment of debt.

Debt payments to income ratio = \frac{1,185}{5,210} = 22.74

5,210

1,185

=22.74

That means the debts are 22.74% of income.

3 0
2 years ago
Electronegativity is<br>____ at the top of the periodic table.​
DanielleElmas [232]

Answer:

Electronegativity is a chemical property at the top of the periodic table

Explanation:

electronegativity is a chemical property that measures the ability of an atom to attract a bonding pair of electrons when it is part of a compound

it's a property of atom that increases as you go to the right and up.

One example is the Pauling scale. it is a numerical scale of electronegativities. It was first developed by Linus Pauling.

it is commonly used to calculate the ability of electronegativity to attract electrons to itself.

The most common electronegative element is Flourine, having an assigned value of 4.0, ranging down to caesium and francium, having the least electronegative at 0.7

3 0
3 years ago
Read 2 more answers
What is the magnitude of the magnetic field at a point midway between them if the top one carries a current of 19.5 A and the bo
Phantasy [73]

Answer:

The magnetic field will be \large{\dfrac{1.4 \times 10^{-4}}{d}} T, '2d' being the distance the wires.

Explanation:

From Biot-Savart's law, the magnetic field (\large{\overrightarrow{B}}) at a distance 'r' due to a current carrying conductor carrying current 'I' is given by

\large{\overrightarrow{B} = \dfrac{\mu_{0}I}{4 \pi}} \int \dfrac{\overrightarrow{dl} \times \hat{r}}{r^{2}}}

where '\overrightarrow{dl}' is an elemental length along the direction of the current flow through the conductor.

Using this law, the magnetic field due to straight current carrying conductor having current 'I', at a distance 'd' is given by

\large{\overrightarrow{B}} = \dfrac{\mu_{0}I}{2 \pi d}

According to the figure if 'I_{t}' be the current carried by the top wire, 'I_{b}' be the current carried by the bottom wire and '2d' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the \bigotimes symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by \bigodot symbol.

Given \large{I_{t} = 19.5 A} and \large{I_{B} = 12.5 A}

Therefore, the magnetic field (\large{B_{t}}) at 'P' due to the top wire

B_{t} = \dfrac{\mu_{0}I_{t}}{2 \pi d}

and the magnetic field (\large{B_{b}}) at 'P' due to the bottom wire

B_{b} = \dfrac{\mu_{0}I_{b}}{2 \pi d}

Therefore taking the value of \mu_{0} = 4\pi \times 10^{-7} the net magnetic field (\large{B_{M}}) at the midway between the wires will be

\large{B_{M} = \dfrac{4 \pi \times 10^{-7}}{2 \pi d} (I_{t} - I_{b}) = \dfrac{2 \times 10^{-7}}{d} = \dfrac{41.4 \times 10 ^{-4}}{d}} T

5 0
3 years ago
The y component of a vector is 36, and the angle between the vector and the x axis is 27 what is the magnitude of the vector
xz_007 [3.2K]

Answer:

Magnitude of Vector = 79.3

Explanation:

When a vector is resolved into its rectangular components, it forms two vector components. These components  are named as x-component and y-component, they are calculated by the following formulae:

x-component of vector = (Magnitude of Vector)(Cos θ)

y-component of vector = (Magnitude of Vector)(Sin θ)

where,

θ = angle of the vector with x-axis = 27°

Therefore, using the values in the equation of y-component, we get:

36 = (Magnitude of Vector)(Sin 27°)

Magnitude of Vector = 36/Sin 27°

<u>Magnitude of Vector = 79.3</u>

3 0
3 years ago
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