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Katena32 [7]
2 years ago
13

You glide 28 units to the +y-direction with respect to the +x-axis, then move 32 units with respect to the +x-direction. What is

the resultant vertical magnitude of your movement while gliding on air? (Hint: Use the Pythagorean theorem)
Physics
1 answer:
NNADVOKAT [17]2 years ago
4 0

This question can be solved by using Pythagora's Theorem.

The resultant magnitude of the movement is "42.5 units".

The x and y components of the movement are given. We can use Pythagora's Theorem to find the resultant of these movements. Hence, applying the Pythagora's Theorem<em>:</em>

d = \sqrt{d_x^2+d_y^2}

where,

d = resultant movement = ?

d_x = movement in x direction = 32 units

d_y = movement in y direction = 28 units

Therefore,

d = \sqrt{(32\ units)^2+(28\ units)^2}

<u>d = 42.5 units</u>

Learn more about Pythagora's Theorem here:

brainly.com/question/343682?referrer=searchResults

The attached picture shows Pythagora's Theorem<em>.</em>

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Radar uses radio waves of a wavelength of 2.9 m . The time interval for one radiation pulse is 100 times larger than the time of
Mandarinka [93]

Answer:

145 m

Explanation:

Given:

Wavelength (λ) = 2.9 m  

we know,

c = f × λ  

where,

c = speed of light ; 3.0 x 10⁸ m/s

f = frequency  

thus,

f=\frac{c}{\lambda}

substituting the values in the equation we get,

f=\frac{3.0\times 10^8 m/s}{2.9m}

f = 1.03 x 10⁸Hz  

Now,

The time period (T) = \frac{1}{f}

or

T =  \frac{1}{1.03\times 10^8}  = 9.6 x 10⁻⁹ seconds  

thus,

the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s  

Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s  

Now,

For radar to detect the object the pulse must hit the object and come back to the detector.

Hence, the shortest distance will be half the distance travelled by the pulse back and forth.

Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}  

Thus, the minimum distance to target = \frac{290}{2} = 145 m

6 0
3 years ago
A testing instrument that's used to measure electrical signals in a circuit and display them as waveforms on a screen is called
disa [49]
A testing instrument that's used to measure electrical signals
in a circuit and display them as waveforms on a screen is called
an oscilloscope.

8 0
3 years ago
A firewoman dropped a person onto the safety net. Right before the person hit the net he had a
sergejj [24]

Answer:

The Mass of a person is calculated to be 28.6kg .

Explanation:

This is based on Kinetic energy and we know, that Kinetic energy is the energy possessed by body by virtue of its motion .

It can be calculated by expression :

K.E=1/2mv²

Velocity of a person = 11.2m/sec

Kinetic energy = 1800J

Mass of person = ?

We know ,

K.E=1/2mv²

so, putting values we have :

1800=1/2 x m x (11.2)²

That is ,

m=1800 x 2 /11.2 x 11.2

or

m=3600/125.44

m = 28.6 kg

6 0
3 years ago
Does anyone know what the answers are?
baherus [9]

Answer:

Option (C) is the answer

Explanation:

may be it is possible if that we stand so far

4 0
3 years ago
Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v
Semenov [28]

Answer:

A)Object 1 has the greater magnitude of its momentum.

B)The objects 2 have the greater kinetic energy.

Explanation:

For object 1 :

v₁ = v  ,m₁ = 2 m

For object 2 :

v_2=2\sqrt{v} ,m₂=m

We know that linear momentum given as

P = M V

M=Mass , V=Velocity

For object 1 :

P₁ =m₁ v₁

P₁ =2 m v

For object 2

P_2=m_2v_2

P_2=2m\sqrt {v}

We can say that object 1 have more momentum.

The kinetic energy

KE_1=\dfrac{1}{2}m_1v_1^2

KE_1=\dfrac{1}{2}\times 2m\times v^2

KE_1=mv^2

KE_2=\dfrac{1}{2}m_2v_2

KE_2=\dfrac{1}{2}\times m\times 4v^2

KE_2=2mv^2

Therefore both the object 2 have higher kinetic energy.

7 0
3 years ago
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