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scoray [572]
3 years ago
7

(3) A Ninja motorcycle is moving down I95 at 160 miles per hour (72 m/s) and a cop uses a radar gun to measure the speed. Using

the formula:
( λ’ -λo)/λo =v/c with a laboratory wavelength of 2.8 cm, can you answer whether of not the radar gun uses the doppler effect to directly measure speed from the motorcycle?
Physics
1 answer:
Virty [35]3 years ago
5 0

Answer:

it does use it at doppler

Explanation:

My dad told me the hes a cop so yw

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An increase in humidity can strengthen the water cycle, because humidity is essentially boosted evaporation. When you have evaporation, that comes automatically with condensation and precipitation, so rain and cloud cover increases.

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A wheel of radius 25cm has eight spokes. It is mounted on a fixed axle and is rotating at a constant angular speed w. You shoot
spayn [35]

Explanation:

We will assume that the rim of the wheel is also very thin, like the spokes. The distance <em>s</em><em> </em><em> </em>between the spokes along the rim is

s = \frac{1}{8}C = \frac{1}{8}(2\pi)(0.25\:\text{m}) = 0.196\:\text{m}

The 20-cm arrow, traveling at 6 m/s, will travel its length in

t = \dfrac{0.2\:\text{m}}{6\:\text{m/s}} = \dfrac{1}{30}\:\text{s}

The fastest speed that the wheel can spin without clipping the arrow is

v = \dfrac{s}{t} = \dfrac{0.196\:\text{m}}{\left(\dfrac{1}{30\:\text{s}}\right)} = 5.9\:\text{m/s}

The angular velocity \omega of the wheel is given by

\omega = \dfrac{v}{r} = \dfrac{5.9\:\text{m/s}}{0.25\:\text{m}} = 23.6\:\text{rad/s}

In terms of rev/s, we can convert the answer above as follows:

23.6\:\dfrac{\text{rad}}{\text{s}}×\dfrac{1\:\text{rev}}{2\pi\:\text{rad}} = 3.8\:\text{rev/s}

As you probably noticed, I did the calculations based on the assumption that I'm aiming for the edge of the wheel because this is the part of the wheel where a point travels a longer linear distance compared to ones closer to the axle, thus giving the arrow a better chance to pass through the wheel without getting clipped by the spokes. If you aim closer to the axle, then the wheel needs to spin slower to allow the arrow to get through without hitting the spokes.

3 0
3 years ago
Which of the following is an example of an
olga55 [171]

Answer:

c. mandible

Explanation:

7 0
4 years ago
A soccer ball is kicked from the ground with an initial speed of 20.1 m/s at an upward angle of 47.8˚. A player 53.0 m away in t
e-lub [12.9K]

Answer:3.95 m/s

Explanation:

Given

Initial velocity(u)=20.1 m/s

launch angle=47.8^{\circ}

Player is 53 m away

Range of projectile

R=\frac{u^2sin2\theta }{g}

R=\frac{20.1^2\times sin95.6}{9.8}

R=41.02 m

so he need to run 53-41.02=11.98 m

Time of flight of projectile =\frac{2usin\theta }{g}

T=3.03 s

thus average speed of boy s_{avg}=\frac{11.98}{3.03}=3.95 m/s

5 0
3 years ago
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