Answer:
3×10^-12 C
Explanation:
The total of the three charges is ...
(-3 +8 +4)×10^-12 C = 9×10^-12 C
Assuming the charge is equally distributed between the balls when they are brought in contact, the charge on each ball will be ...
(9/3)×10^-12 C = 3×10^-12 C
Answer:
Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines.
Answer:
0.001152m
Explanation:
Linear expansivity of a material is the change in length of the material per unit length per degree rise in temperature. Mathematically,
¢ = ∆L/L1∆°C
¢ is the linear expansivity of the material = 12 x 10⁻⁶ °C⁻¹
Where ∆L is the change in length = L2-L1
L2 is the final length = ?
L1 is the initial length = 12m
∆°C is the change in temperature = °C2 - °C1 = 50-(-30) = 80°C
Substituting this values inside the formula to get the final length L2 after expansion, we have;
12 x 10⁻⁶ °C⁻¹ = L2-12/12×80
12 x 10⁻⁶ °C⁻¹ = L2-12/960
L2-12= 960×12 x 10⁻⁶ °C⁻¹
L2-12 = 0.001152
L2 = 12+0.001152
L2 = 12.001152m
Expansion will be the change in length L2-L1 = 12.001152-12
= 0.001152m
The expansion cracks between the slabs should be 0.001152m wide to prevent buckling
Answer:
= 351.84 J
Explanation:
Using the conservation of energy K:
so:
where m is the mass, v the initial velocity, is the kinetic energy of the mass as it clears the fence, g the gravity and h the altitude.
Then, replacing values, we get:
solving for :
= 351.84 J
Oh what a sneaky problem !
The "range" of a projectile is how far out away from the gun it goes
before it falls to the ground.
The question is asking you: "What angle should you aim the gun
above the horizon so that the bullet doesn't go <em>any</em> distance away
from the gun, and it hits the ground exactly where the gun is "
And there are two different answers. Really sneaky !
Can you think of how you could fire the gun so that the bullet would
hit the ground right under the gun ? How about pointing the gun at
the ground ... aiming 90 degrees <em>below</em> the horizon ? That would
certainly do it. Is there another way to do it ?
How about aiming the gun straight up in the air ... 90 degrees <em>above</em>
the horizon ? Then it goes up, up, up, runs out of steam, stops rising,
starts falling, comes down, down, down, and hits the ground right where
the gun was.
As long as there's no air and no wind, the two angles are +90 degrees
and -90 degrees above the horizon.
' +90 above ' means straight up. ' -90 above ' means straight down.
