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Crank
2 years ago
6

A light flashes at position x=0m. One microsecond later, a light flashes at position x=1000m. In a second reference frame, movin

g along the x-axis at speed v, the two flashes are simultaneous. Is this second frame moving to the right or to the left relative to the original frame?
Physics
1 answer:
padilas [110]2 years ago
7 0

Answer:

To the right relative to the original frame.

Explanation:

In first reference frame <em>S</em>,

Spatial interval of the event, \rm \Delta x=1000\ m-0\ m=1000\ m.

Temporal interval of the event, \rm \Delta t = 1\ \mu s=10^{-6}\ s.

In the second reference frame <em>S'</em>, the two flashes are simultaneous, which means that the temporal interval of the event in this frame is \rm \Delta t'=0\ s.

The speed of the frame <em>S' </em>with respect to frame <em>S</em> = v.

According to the Lorentz transformation,

\rm \Delta t'=\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}\left( \Delta t-\dfrac{v\Delta x}{c^2}\right ).\\\\Since,\ \Delta t'=0,\\\therefore \dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}\left( \Delta t-\dfrac{v\Delta x}{c^2}\right )=0\\\Rightarrow \Delta t-\dfrac{v\Delta x}{c^2}=0\\\dfrac{v\Delta x}{c^2}=\Delta t\\v=\dfrac{c^2\Delta t}{\Delta x }.\\\\Also, \ \Delta t,\ \Delta x>0\ \Rightarrow v>0.

And positive v means the velocity of the second frame<em> </em><em>S'</em> is along the positive x-axis direction, i.e., to the right direction relative to the original frame <em>S</em>.

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