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masha68 [24]
2 years ago
6

A pressure gauge at elevation 12m at the side of a tank containing a liquid reads 80 kpa. Another gauge at elevation 7m reads 12

0 kpa. Compute the specific gravity of the liquid?
Chemistry
1 answer:
Vlad1618 [11]2 years ago
7 0

The specific gravity of the liquid is 8 kN/m³.

<h3>What is specific gravity?</h3>

The specific gravity is given as the ratio of the density of the substance with respect to the reference material.

The specific gravity with liquids at varying pressure is given with the Bernoulli's equation as:

\rm \dfrac{P_1}{\gamma} \;+\;z_1 \;=\;\dfrac{P_2}{\gamma}\;+\;z_2

Substituting the pressure (P), the elevation (z), the specific gravity (γ) is given as:

\rm \dfrac{P_1}{\gamma}-\dfrac{P_2}{\gamma}=z_2-z_1\\\\\gamma =\dfrac{P_1-P_2}{z_2-z_1}\\\\\gamma=\dfrac{120-80\;kpa}{12-7\;m}\\\\\gamma=8kN/m^3

Thus, the specific gravity of the liquid is 8 kN/m³.

Learn more about specific gravity, here:

brainly.com/question/9100428

#SPJ4

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Answer:

a) Ecell = 0.5123 V

b) Ecell =  0.4695 V

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Explanation:

a)

The reaction at the cathode is represented as follows:

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The number of moles of the electrons that are involved is equal to n = 2

Standard cell potential equals Eo = Eocathode - Eoanode = 0.34 V- (-0.13 V) = 0.47 V

 The initial cell potential can be calculated with the following formula:

Ecell = Eocell - - 0.0592 / n) log ([(Pb2 +)] / [(Cu2 +)]) = 0.47 - (0.0592 / 2) log (0.052 / 1.4) = 0.5123 V

b)

The reaction in the cell is equal to:

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The concentration of Cu2 that gives the exercise is equal 0.2 M

Therefore, the change in concentration for Cu2 + is equal to:

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We use the formula from part a)

Ecell = Eocell - (0.0592 / n) log ([(Pb2 +)] / [(Cu2 +)]) = 0.47 - (0.0592 / 2) log (1,252 / 1.2) = 0.4695 V

c)

To find the concentration of Pb2 + when there is a potential change in the cell of 0.37 V, we must clear the concentration of Pb2 + from the following formula:

Eccell = Echocell - (0.0592 / n) log (([Pb2 +]) / ([Cu2 +]))

0.0296 log ([Pb2 +] / [Cu2 +]) = (Eocélula - Ecélula / 0.0296)

Clearing Pb2 +:

[Pb2 +] = 4.75 M

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