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antoniya [11.8K]
3 years ago
11

Calculate the molarity of a solution containing 15.2 grams of NaCl dissolved in 2.5 L of solution.

Chemistry
1 answer:
Advocard [28]3 years ago
8 0

Answer:

en español por favor

Explanation:

no seeeed perdona

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If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
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3 years ago
Atomic Structure of 14 Elements Please use the periodic table of elements to answer the questions below. How can you determine t
andrew-mc [135]

Silicon has 14 protons Potassium has 19 electrons The neutrons are equal to the mass number minus the atomic number. Or the big number minus the small number on the periodic table. hydrogen 1 does not have a neutron.

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7 0
3 years ago
Read 2 more answers
How many grams of solid Ca(OH)2 (74.1 g/mol) are required to make 500 ml of a 3 M solution?
mars1129 [50]

Answer:

111.15 g are required to prepare 500 ml of a 3 M solution

Explanation:

In a 3 M solution of Ca(OH)₂ there are 3 moles of Ca(OH)₂ per liter solution. In 500 ml of this solution, there will be (3 mol/2) 1.5 mol Ca(OH)₂.

Since 1 mol of Ca(OH)₂ has a mass of 74.1 g, 1.5 mol will have a mass of

(1.5 mol Ca(OH)₂ *(74.1 g / 1 mol)) 111.15 g. This mass of Ca(OH)₂ is required to prepare the 500 ml 3 M solution.

3 0
3 years ago
A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253
german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. \dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L

So, the new volume is 1.45 L.

6 0
3 years ago
so how many moles of Fe are in 3.10 mole of iron oxide FeO still waiting for answer please, my grandchild needs help that I can'
alisha [4.7K]
The answer is 3.10 because it's still the same amount moles of iron.
7 0
3 years ago
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