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Evgen [1.6K]
2 years ago
5

Acids which contain only hydrogen and a single other element are referred to as.

Chemistry
1 answer:
Pachacha [2.7K]2 years ago
8 0

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  • A binary acid is an acid that consists of hydrogen and one other element.
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How many significant figures<br> are in this number?<br> 107.051
Anestetic [448]

Answer:

there are 6 significant figures in 107.051

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3 years ago
Read 2 more answers
Is helium a metal, non metal or metalloid?
ioda

Helium is a nonmetal. There are several reasons for this, it is unable to donate electrons and It has an extremely low melting point.

4 0
3 years ago
A student has a mixture of solid sand and nacl(aq)in a flask to obtain solid nacl from this mixture the student should
maria [59]
In order to obtain solid NaCl, the student should do a few steps.

First, he/she should do filtration. Pass the mixture through a filter paper, where all the sand should be filtered out already because they're not dissolved in the solution plus they're too small to pass through the filter paper.

Next, the filtrate should be left with NaCl (aqueous state). To seperate NaCl with the liquid, the student can either do evaporation or crystallization, depending on how pure or fast he/she wants the results to be. Evaporation involves heating the beaker or whatever apparatus under the bunsen burner until all the liquid has evaporated. Then, some white powder should be left, they're NaCl solid. For crystallization, the student should just put the beaker on a room condition environment, and wait. They might have to wait a month or so for the liquid to completely evaporate itself and left with clear and pure NaCl crystals.
5 0
3 years ago
an element has an isotope with a mass of 203.973 amu and and abundance of 1.40%. another isotope has a mass of 205.9745 amu with
ryzh [129]

Answer is: the average atomic mass 217.606 amu.

Ar₁= 203.973 amu; the average atomic mass of isotope.

Ar₂ = 205.9745 amu.

Ar₃ = 206.9745 amu.

Ar₄ = 207.9766 amu.

ω₁ = 1.40% = 0.014; mass percentage of isotope.

ω₂ = 24.10% = 0.241.

ω₃ = 22.10% = 0.221.

ω₄ = 57.40% = 0.574.

Ar = Ar₁ · ω₁+ Ar₂ · ω₂ + Ar₃ · ω₃ + Ar₄ · ω₄.  

Ar = 203.973 amu · 0.014 + 205.9745 amu · 0.241 + 206.9745 amu · 0.221 + 207.9766 amu · 0.574.

Ar = 2.855 amu + 49.632 amu + 45.741 amu + 119.378 amu.

Ar = 217.606 amu.

But abundance of isotopes is greater than 100%.

It should be lead, with the fourth isotope weighs 207.9766 amu and an abundance of 52.40.

7 0
3 years ago
QUESTION 20
Assoli18 [71]

Answer:

49.56

Explanation:

5 0
2 years ago
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