Answer:
The answer to your question is: Molarity = 0.83
Explanation:
Data
5% by mass
Molarity = ?
density = 1.05 g/ml
Molecular weight (CH₃COOH) = 24 + 32 + 4 = 60 g
Process
- Percent by mass means 5 g of vinegar in 100 ml of solution
- Calculate the moles of vinegar in the solution
60 g of vinegar ------------ 1 mol
5 g of vinegar ----------- x
x = (5 x 1) / 60
x = 0.0833 mol of vinegar
Formula
Molarity = moles of vinegar / volume (liters)
Substitution
Molarity = 0.0833 / 0.1
Molarity = 0.83