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Alisiya [41]
3 years ago
9

The vinegar solution you can purchase at the store is about 5% by mass acetic acid. It will be easier for you to assess your res

ults if you convert 5% by mass acetic acid from weight percent to molarity since your experimental results will be in molarity. Show this conversion in your notebook. You will need to approximate the density of the vinegar solution to complete this conversion.
Chemistry
1 answer:
Semmy [17]3 years ago
4 0

Answer:

The answer to your question is: Molarity = 0.83

Explanation:

Data

5% by mass

Molarity = ?

density = 1.05 g/ml

Molecular weight (CH₃COOH) = 24 + 32 + 4 = 60 g

Process

- Percent by mass means 5 g of vinegar in 100 ml of solution

- Calculate the moles of vinegar in the solution

                         60 g of vinegar ------------  1 mol

                           5 g  of vinegar  -----------  x

                           x = (5 x 1) / 60

                          x = 0.0833 mol of vinegar

Formula

Molarity = moles of vinegar / volume (liters)

Substitution

Molarity = 0.0833 / 0.1

Molarity = 0.83

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Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density of 1010 g/L. If vinegar is 0.80
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Hi! I'm on the last question of my homework and I'm stuck on it and was wondering if anyone could help me
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I am not sure but this is what I think

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Which is Density= Mass/Volume

Convert the mass in g
92.5 kg = 92,500g


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= 11,753.5 ml

Now since we have to give the answer in liters we can just divide by 1000 and get
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