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2 years ago

PLS I WILL GIVE BRAINLY How do the number of violence electrons of the light metals compared to those heavier than boron

Chemistry

1 answer:

SCORPION-xisa [38]2 years ago

4 0

The valence electron of the light metals are all in the range of 1 to 3.

<h3>What are Valence electron ?</h3>

Valence Electron is the number of electrons in the outer shell of an atom which participate in bond formation.

Number of Valence Electron in Boron is 3 and other light metals lighter than Boron have 1 , 2 of Lithium and Beryllium respectively,

The valence electron of the light metals are all in the range of 1 to 3.

To know more about Valence Electron

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3 years ago

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3 years ago

Read 2 more answers

Linda performed the following trials in an experiment. Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0

nexus9112 [7]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

To calculate the amount of heat absorbed or released, we use the following equation:

$q=mc\Delta T$ .....(1)

where, q = amount of heat absorbed or released.

m = mass of the substance

c = heat capacity of water = 4.186 J/g ° C

$\Delta T$ = Change in temperature

<u>For Trial 1:</u>

We are given:

$m=30g\\\Delta T=[40-0]^oC=40^oC\\q=?J$

Putting values in equation 1, we get:

$q=30g\times 4.186J/g^oC\times 40^oC$

q = 5023.2 J

<u>For trial 2:</u>

We are given:

$m=40g\\\Delta T=[40-30]^oC=10^oC\\q=?J$

Putting values in equation 1, we get:

$q=40g\times 4.186J/g^oC\times 10^oC$

q = 1674.4 J

Heat gained by Trial 1 than trial 2 = $(5023.2-1674.4)J=3347J$

Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.

Thus, the correct answer is Option b.

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3 years ago