The momentum of each cart is given by:
where
m is the mass of the cart
v is its velocity (at the bottom of the ramp)
To answer the problem, let's calculate the momentum of each of the 4 carts:
1)
2)
3)
4)
Therefore, the cart with greatest momentum is cart 3, so the right answer is
<span>- trial 3, because this trial has a large mass and a large velocity</span>
-- Depending on the time of the year, the sun's rays strike Earth
most directly somewhere between the Tropic of Cancer and the
Tropic of Capricorn.
That's a belt around the Earth's "middle" called the "Tropic Zone".
The equator is in the middle of it, the Tropic of Cancer is 23.5° North
of the equator, and the Tropic of Capricorn is 23.5° degrees South of it.
The sun's rays can never be totally direct, straight down onto the Earth's
surface, anywhere outside this belt.
-- The sun's rays strike Earth least directly wherever, and whenever,
the sun is setting.
Answer:
The spacing between the slits is 
Explanation:
From the question we are told that
The wavelength of the light is 
The distance of the slit from the screen is 
The number of bright fringe is 
The length the fringes span is 
The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as
Where d is the distance between the slits
is the fringe width which can also be evaluated as
Substituting values
Making d the subject of formula in the above equation
Substituting values
Answer:
Force of friction, f = 751.97 N
Explanation:
it is given that,
Mass of the car, m = 1100 kg
It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.
From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.
f = 751.97 N
So, the force of friction on the car is 751.97 N. Hence, this is the required solution.
