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Oliga [24]
3 years ago
14

A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is

decreasing at a rate of 3.1m/s2.
What is the student's mass?
What is the net force on the student?
What value does the scale read?
Physics
1 answer:
jasenka [17]3 years ago
3 0

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, F_{net} = The weight of the student + The inertia force of the slowing elevator

∴ The net force, F_{net} = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

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by using the work- energy theorem which states that the kinetic energy of the the electron must equal the work done use in accelerating the electron.

kinetic energy = \frac{mv^{2} }{2},  potential energy = qV

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Answer:

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Explanation:

Let say the speed of the bicycle while he moves towards the city is "v"

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now we know that total time of the motion is 19 hr

so we will have

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by solving above equation we have

v = 10 mph

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