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Zarrin [17]
3 years ago
9

Through which material would you expect sound waves to move fastest? O A. Iron O B. Water O c. Air O D. Milk​

Physics
2 answers:
Alexxx [7]3 years ago
8 0

Answer:

Solids

Is this what your looking for, It might tell you the answer?

zheka24 [161]3 years ago
7 0

Answer:

iron

Explanation:

ap3x

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Does coefficient of linear expansion depends on length​
nlexa [21]

Answer:

yes

Explanation:

As the formula is α= ΔL/L*ΔT  where alpha (α) is the sign of coefficient of linear expansion

5 0
3 years ago
When a piece of wood burns, it makes heat, light, and ash. Therefore, it is an example of what type of change
Nastasia [14]
It is a chemical change
8 0
3 years ago
Read 2 more answers
The change in velocity during a measurable time interval, divided by the time interval, is the _____.
scoray [572]
Hello!


Let's put it into symbols:

Change in velocity = \mathsf{V_f - V_i=\Delta V}
A measurable interval: \mathsf{\Delta t}

This division is:

\mathsf{\dfrac{\Delta V}{\Delta t}}

We can recognize this as the Average Acceleration \mathsf{a_m}
5 0
3 years ago
How many revolutions per minute would a 20 m -diameter ferris wheel need to make for the passengers to feel "weightless" at the
timurjin [86]
The general equation for the forces acting on the passengers at the topmost point of the ferris wheel is
mg - R = m \omega^2 r
where
mg is the weight of the passengers
R is the normal reaction of the cabin
m \omega^2 r is the centripetal force

In order to feel weightless, the normal reaction felt by the passengers should be zero. Therefore, the equation becomes:
mg=m \omega^2 r
or
g=\omega^2 r
where \omega is the angular frequency of the wheel and r is its radius. Since we know its radius, 
r= \frac{20 m}{2}=10 m
we can calculate the angular frequency:
\omega= \sqrt{ \frac{g}{r} } = \sqrt{ \frac{9.81 m/s^2}{10 m} } =0.99 rad/s
From which we find the frequency at which the ferris wheel should rotate:
f= \frac{\omega}{2 \pi}= \frac{0.99 rad/s}{2 \pi}=0.158 s^{-1}
This is the number of revolutions per second, so the number of revolutions per minute will be
f=0.158 s^{-1} \cdot 60 = 9.48 min^{-1}
6 0
3 years ago
Two charges and are separated by 10cm on the x- axis. Q2 is at the origin and Q1 is 12cm to the right.
Evgen [1.6K]

Answer:

Explanation:

Q₂ is at the origin and Q₁ is at 12 cm on x -axis

Force between Q₁ and Q₂

= K x Q₁ x Q₂ / .12 where k is a constant equal to 9x 10⁹

Force F = 9 x 10⁹ x Q₁ x Q₂ / .12²

= 625 x 10⁹ x Q₁Q₂ N

This is the force each one exerts on other . So electric force on Q₂ due to Q₁ is 625 x 10⁹ x Q₁Q₂ N . Its direction is towards left as both will repel each other.

b)

Electric field due to charge Q₂ at - 2 cm

= 9 x 10⁹ x Q₂ / .02²

= 22500 x 10⁹ x Q₂ N/C , towards left .

Electric field due to charge Q₁ at - 2 cm

= 9 x 10⁹ x Q₁ / .14²

= 459.18 x 10⁹ x Q₁  N/C , towards left

As both the fields are to the same direction

Net field = 75 x 10⁹ x Q₂ + 459.18 x 10⁹ x Q₁

10⁹ ( 22500 x Q₂ + 459.18  x Q₁ ) N/C .

Direction will be towards left.

8 0
2 years ago
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