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Sloan [31]
2 years ago
10

How many grams of Al would be needed to displace all of the copper ions in 71.8 mL of 0.610 M CuSO4?

Chemistry
1 answer:
Galina-37 [17]2 years ago
4 0

The amount of Al that would be needed will be 0.79 grams

<h3>Stoichiometric calculations</h3>

From the equation of the reaction below:

2 Al + 3 CuSO_4 --- > Al_2(SO_4)_3 + 3 Cu

The mole ratio of Al to CuSO_4 is 2:3.

Mole of 71.8 mL. 0.610 M  CuSO_4 = 0.610 x 71.8/1000 = 0.0438 moles

Equivalent mole of Al = 2/3 x 0.0438 = 0.029 moles

Mass of o.o29 moles Al = 0.029 x 26.98 = 0.79 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

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Sauron [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The partial pressure is P_p= 737.5 mm \ of  \ Hg

Explanation:

The Partial pressure of H_2 is mathematically represented as

           P_p = P_T -P_w

Where P_T is the total pressure of water with a value of 15.5 mm of Hg

           P_w is the partial pressure of water with a value 753 mm of Hg

Now substituting values

          P_p = 753-15.5

               P_p= 737.5 mm \ of  \ Hg

       

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3 years ago
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Entropy can be thought of as the degree of disorganization of a system.<br> TRUE<br> FALSE
Mice21 [21]

Answer:

True

Explanation:

The entropy of a system denoted by S is a thermodynamic function that increases in value when there are more ways to arrange the particles in the system. Some spontaneous chemical processes are entropy driven. An increase in entropy is said to drive the dissolution of ionic salts along with the evaporation of water are related to the spreading out of energy.

The entropy of a system can be taken as a measure of disorder of a system. In a spontaneous chemical process, the entropy of the universe is said to increase. ΔSunivu>0. Making the answer true.

7 0
2 years ago
The titration of 78.5 mL of an unknown concentration H3PO4 solution requires 134 mL of 0.224 M KOH solution. What is the concent
Katyanochek1 [597]

Answer:

0.127 M.

Explanation:

The balanced equation for the reaction is given below:

H3PO4 + 3KOH —› K3PO4 + 3H2O

From the balanced equation above, we obtained the following data:

Mole ratio of acid, H3PO4 (nA) = 1

Mole ratio of base, KOH (nB) = 3

Data obtained from the question include:

Volume of acid, H3PO4 (Va) = 78.5 mL

Molarity of acid, H3PO4 (Ma) =...?

Volume of base, KOH (Vb) = 134 mL

Molarity of base, KOH (Mb) = 0.224 M

The concentration of the acid, H3PO4 can be obtained as follow:

MaVa / MbVb = nA/nB

Ma x 78.5 / 0.224 x 134 = 1/3

Cross multiply

Ma x 78.5 x 3 = 0.224 x 134 x 1

Divide both side by 78.5 x 3

Ma = (0.224 x 134 x 1) /(78.5 x 3)

Ma = 0.127 M

Therefore, the concentration of the acid, H3PO4 is 0.127 M.

3 0
3 years ago
The periodic table is an arrangment of the chemical elements, ordered by atomic number, into families, and by doing so illustrat
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Answer:

Cesium and Neon

Explanation:

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8 0
3 years ago
) PABA refers to para-aminobenzoic acid which is used in some sunscreen formulations. If a 0.055 M solution of PABA has a pH of
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Answer: K_a of PABA is 0.000022

Explanation:

NH_2C_6H_5COOH\rightarrow H^++NH_2C_6H_5COO^-

  cM              0             0

c-c\alpha        c\alpha          c\alpha

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.055 M and \alpha = ?

K_a=?

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2.96=-log[H^+]

[H^+]=1.09\times 10^{-3}

[H^+]=c\times \alpha

1.09\times 10^{-3}=0.055\times \alpha

\alpha=0.02

Putting in the values we get:

K_a=\frac{(0.055\times 0.02)^2}{(0.055-0.055\times 0.02)}

K_a=0.000022

Thus K_a of PABA is 0.000022

5 0
2 years ago
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