Answer:
False
Explanation:
In miles per hour, light speed is about 670,616,629 mph
Answer:
60 N
Explanation:
This is just Newton's Second Law
F = m*a
F = ?
m = 12 kg
a = 5 m/^2
F = 5*12 = 60 Newtons
Answer:
at t=46/22, x=24 699/1210 ≈ 24.56m
Explanation:
The general equation for location is:
x(t) = x₀ + v₀·t + 1/2 a·t²
Where:
x(t) is the location at time t. Let's say this is the height above the base of the cliff.
x₀ is the starting position. At the base of the cliff we'll take x₀=0 and at the top x₀=46.0
v₀ is the initial velocity. For the ball it is 0, for the stone it is 22.0.
a is the standard gravity. In this example it is pointed downwards at -9.8 m/s².
Now that we have this formula, we have to write it two times, once for the ball and once for the stone, and then figure out for which t they are equal, which is the point of collision.
Ball: x(t) = 46.0 + 0 - 1/2*9.8 t²
Stone: x(t) = 0 + 22·t - 1/2*9.8 t²
Since both objects are subject to the same gravity, the 1/2 a·t² term cancels out on both side, and what we're left with is actually quite a simple equation:
46 = 22·t
so t = 46/22 ≈ 2.09
Put this t back into either original (i.e., with the quadratic term) equation and get:
x(46/22) = 46 - 1/2 * 9.806 * (46/22)² ≈ 24.56 m
Answer:
<em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>use</em><em> </em><em>formula</em><em> </em><em>of</em><em> </em><em>volume</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>volume</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>cuboid</em><em>.</em><em> </em><em>(</em><em> </em><em>i.e</em><em> </em><em>v</em><em> </em><em>=</em><em> </em><em>l</em><em> </em><em>×</em><em>b</em><em> </em><em>×</em><em>h</em><em>)</em>
Explanation:
here, let your length of cuboid be x cm, breadth be y cm and height be z cm .
now, formula to find volume of cuboid = length ×
breadth × height.
so, v( volume)= l (length)× b (breadth)× h (height)
or, v= x cm × y cm × z cm
therefore, volume is xyz cm^3..... answer.
<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>