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lana [24]
3 years ago
10

 i will give u BRAINILIEST!!!!

Physics
1 answer:
galina1969 [7]3 years ago
7 0
There you can give her brainiest
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Please help need answer asp
sdas [7]
D cardio-respiratory Endurance\

3 0
2 years ago
What does Rockstrom mean by the need to "bend the curves"?
umka21 [38]

Answer: Rockstrom meant that it's going to be a challenging decade and that people will need to work hard and also bend the curve by thinking around the curve.

Explanation:

Some years ago, Johan Rockström, who was the executive director of Stockholm Environment Institute, and a professor at Stockholm University, was the head of an international team that was assembled in defining planetary boundaries.

The that was gathered to speak regarding issues that pertained to the Earth ane how it can be protected from being infiltrated ad protecting it from failing. During the conversation, Rockstrom said that it's going to be a challenging decade and that people will need to work hard and also bend the curve by thinking around the curve.

4 0
2 years ago
A man 6 feet tall walks at a rate of 6 feet per second away from a light that is 15 feet above the ground.
Tems11 [23]

Answer:(a)10 ft/s

(b)4 ft/s

Explanation:

Given

height of light =15 feet

height of man=6 feet

\frac{\mathrm{d} x}{\mathrm{d} t}=6 ft/s

From diagram

\frac{15}{y}=\frac{6}{y-x}

5(y-x)=2y

3y=5x

differentiate both sides

3\times \frac{\mathrm{d} y}{\mathrm{d} t}=5\times \frac{\mathrm{d} x}{\mathrm{d} t}

Tip of shadow is moving at the rate of

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{5}{3}\times 6=10 ft/s

(b)rate at which length of his shadow  is changing

Length of shadow is y-x

differentiating w.r.t time

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=\frac{\mathrm{d} y}{\mathrm{d} t}-\frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=10-6=4 ft/s

7 0
3 years ago
The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply
kykrilka [37]

Answer: Got It!

<em>Explanation:  </em>let s = speed at launch

v = 0 at top = s sin 63 - g t

so at top

t = s sin 63/g = .0909 s

h = 13.6 = s sin 63 t - 4.9 t^2

13.6 = .081s^2 - .0405 s^2

s^2 = 336

s = 18.3 m/s

0  0

4 0
2 years ago
Why is weathering slow in cold, dry places?
Alexxandr [17]

Rate of weathering depends on temperature and moisture. Cold dry places have less water to weather things


Hope this helped!

Don't forget: Mark Brainliest!

Have a good day :)

6 0
3 years ago
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