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cricket20 [7]
2 years ago
12

A teacher wants to demonstrate that the radioactive source emits alpha beta and gamma radiation.

Physics
1 answer:
Mashcka [7]2 years ago
6 0

It is possible to distinguish between these types of radiation by the use of an electrostatic field.

<h3>What is a radioactive source?</h3>

A radioactive source is a source that emits radiation such as alpha, beta and gamma radiation. We can be able to distinguish between these types of radiation by the use of an electrostatic field.

The gamma rays is undeflated by the field, the alpha ray is deflated to the negative part of the field while the beta rays is deflated by the positive part of the field.

Learn more about radioactive source: brainly.com/question/12741761?

#SPJ1

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What are the SI units of thermal conductivity?​
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The SI unit of thermal conductivity is watts per meter-kelvin (W/(m⋅K)).

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The leading cause of air pollution is?
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Combustion Engine Exhaust----Cars, trucks, jet airplanes and other combustion engine vehicles cause air pollution. The exhaust from these contains carbon monoxide, nitrous oxide and gaseous oxide. This type of air pollution creates smog
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Equation of orbit under central force​
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3 years ago
Can someone please help with this. "A ball is thrown vertically upward with a speed of 26.6 m/s. How high does it rise? The acce
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v^2=u^2+2as

0=26.6^2-2x9.8xs

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3 years ago
An aquarium open at the top has 30-cm-deep water in it. You shine a laser pointer into the top opening so it is incident on the
Setler [38]

Answer:

You must add 8cm of water to the tank

Explanation:

In order to find how much the height is we will use the Snell Refraction law

.

This law relates the index of refraction of the water (n2), the index of refraction of the air (n1), the incidence angle relative to the vertical (theta1) and the refraction angle relative to the vertical (theta2) by using the next equation:

(n1)*(sin(theta1))=(n2)*(sin(theta2))

Then we will find the refraction angle relative to the vertical this way:

(n1/n2)*(sin(theta1))=sin(theta2)

(1/1.33)*(sin(45))=sin(theta2)

Then, theta2=32.12°

Now that we have this information we can imagine a triangle with a 30cm height and a 32.12° angle. This way we can find how much X is, this X will be the distance between the vertical line and the spot the beam hits the bottom, so we can use some trigonometry to find it, this way:

tan(32.12)=(X/30cm)

X=(tan(32.12))*(30cm)

Then, X=18.8cm, we can approximate it to 19cm

Once we have X we will add 5cm to it which is how much the beam needs to be moved, then the new X will be 24cm

Now, with the new horizontal distance we will find the new vertical distance, let´s call it Y, this way we will know how much water we must add to move the beam, then we will have a triangle with a vertical distance called Y, the same 32.12° angle will be used as we are still working with the air-water interface and a 19cm horizontal distance, then:

tan(32.12)=(24cm/Y)

Y=(24cm/tan(32.12))

Then, Y=38cm

In this case, you must add 8cm of water to the tank to move the beam on the bottom 5cm

5 0
3 years ago
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