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FromTheMoon [43]
3 years ago
6

Assume that the stopping distance of a van varies directly with the square of the speed. A van traveling 40 miles per hour can s

top in 70 feet. If the van is traveling 48 miles per​ hour, what is its stopping​ distance?
Physics
1 answer:
Daniel [21]3 years ago
4 0

Answer:

d = 100.8 ft

Explanation:

As we know that initial speed of the van is 40 miles then the stopping distance is given as 70 feet

here we know that

v_f^2 - v_i^2 = 2 ad

so here we have

0^2 - 40^2 = 2 a (70 feet)

now again if the speed is increased to 48 mph then let say the stopping distance is "d"

so we will have

0^2 - 48^2 = 2 a (d)

now divide the above two equations

\frac{40^2}{48^2} = \frac{70 feet}{d}

d = 100.8 ft

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