1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irga5000 [103]
3 years ago
10

At its peak, a tornado is 53.0 m in diameter and carries 465-km/h winds. What is its angular velocity in revolutions per second?

Physics
1 answer:
expeople1 [14]3 years ago
8 0

Answer:

0.7757 rev/s

Explanation:

d = Diameter of the tornado = 53 m

r = Radius of the tornado = 53/2 = 26.5 m

v = Velocity of wind = 465 km/h

Converting velocity to m/s

465=465\times \frac{1000}{3600}=\frac{775}{6}

Angular velocity

\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{\frac{775}{6}}{26.5}\\\Rightarrow \omega=4.87\ rad/s

\omega=4.87\frac{1}{2\pi}=0.7757\ rev/s

∴ Angular velocity is 0.7757 rev/s

You might be interested in
A car's velocity changes from 40 m/s to 30 m/s in 40 seconds. What is the
valina [46]

Answer:

- 0.25m/s²

Explanation:

Given parameters:

Initial velocity  = 40m/s

Final velocity  = 30m/s

Time taken  = 40s

Unknown:

Acceleration of the car  = ?

Solution:

Acceleration is the rate of change of velocity with time.

 So;

  Acceleration  = \frac{Final velocity - Initial velocity }{time }  

 Acceleration  = \frac{30  - 40}{40}    =  - 0.25m/s²

This implies that the car will decelerate at a rate of 0.25m/s²

7 0
3 years ago
Which type of graph would be best for showing the percentage of people in a family with different jobs? A. Circle graph B. Scatt
musickatia [10]

Answer:

A

Explanation:

A circle graph typically represents numbers in percentages, used to visualize a part to whole relationship or a composition

6 0
4 years ago
Plsss help
Ede4ka [16]
Work = force x distance. In units, Joules = Newtons x meters.

So: Work = 50 Newtons x 3 meters

Work  = 150 joules. Answer D is correct

FYI - to ace physics, you should learn to identify these values using their fundamental units:
Force = Newtons = Kg·m/s²
Work = joules = kg·m²/s²
Power = watts = kg·m²/s³

In high school physics, If you learn to arrange equations so the units work out properly for the answer, you'll get most problems correct.
7 0
3 years ago
The brightest star in the night sky in the northern hemisphere is Sirius. Its distance from Earth is estimated to be 8.7 light y
katen-ka-za [31]

Answer:5.11(10)^{13}miles

Explanation:

A light year is a unit of length and is defined as "the distance a photon would travel in vacuum during a Julian year at the speed of light at an infinite distance from any gravitational field or magnetic field. "

In other words: It is the distance that the light travels in a year.  

This unit is equivalent to 5.879(10)^{12}miles, which mathematically is expressed as:

1Ly=5.879(10)^{12}miles

Doing the conversion:

8,7Ly.\frac{5.879(10)^{12}miles}{1Ly}=5.11(10)^{13}miles  This is the distance from Earth to Sirius in miles.

4 0
3 years ago
You and your friend are going bungee jumping! You wait directly below them with a camera. When they leap from the bridge they be
Alex

Answer:

The amplitude  is  A =  90.2 \ m

Explanation:

From the question we are told that

    The frequency of when sound is approaching observer is   f = 392 Hz

     The frequency as the move away from observer  is  f_ a =  330 \ Hz

    The time between the pitch are t =  10 \ s

Here you are the observer and your friends are the source of the sound

The period is mathematically evaluated as

       T =  2 t

as it is the time to complete one oscillation which from on highest pitch to the next highest pitch

Now T can also be mathematically represented as

          T = \frac{2 \pi}{w}

Where  w is the angular velocity

=>   \frac{2 \pi}{w}  =  2 * 10

=>   w =  0.314 \ rad/sec

Now using Doppler Effect,

   The source of the sound is approaching the observer

The

          f = f_o (\frac{v}{v- wA} )

         392  = f_o (\frac{v}{v- wA} )

Where A is the amplitude

    So when the source is moving away from the observer

         f_a =  f_o (\frac{v}{v+ wA} )  

        330  =  f_o (\frac{v}{v+ wA} )  

Here  f_o is the fundamental frequency

Dividing the both equation  we have

           \frac{392}{330}  =  \frac{f_o(\frac{v}{v-wA} )}{f_o(\frac{v}{v+wA}}

           1.1878  = \frac{v+wA}{v-wA}

         1.1878 v -  1.1878 wA = v+wA

        1.1878 v = 2.1878 wA

=>     A =  \frac{(0.1878 * (330))}{(2.1878)* (0.314)}

         A =  90.2 \ m

7 0
3 years ago
Other questions:
  • I a liter jar contains 0.5 moles of gas at a pressure of 2 ATM what is the temperature of the gas
    15·1 answer
  • A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at
    9·1 answer
  • Which of these is caused by a chemical change?
    5·2 answers
  • What is the speed of a truck that travels 10 km in 10 minutes?
    12·2 answers
  • When is zero considered significant​
    12·2 answers
  • A crowbar is used as a lever. The effort force of 40 newtons moves 3 meters. The resistance force of 54 newtons moves 2 meters.
    13·2 answers
  • This is a textbook question, work too please!
    15·1 answer
  • Which of the following statements are true about metallic bonds? A. Metallic bonds hold together atoms with somewhat similar ele
    15·1 answer
  • A soccer player kicks a ball with initial velocity of 10m/s at an angle of 30 degrees above the horizontal.....what is the magni
    12·1 answer
  • The agonist in a movement is the muscle that provides the major force to complete the movement
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!