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2 years ago

6

What are the corresponding minimum and maximum velocities that the rocket experiences? Express your answer as two numbers separa

ted by a comma

1 answer:

Tomtit [17]2 years ago

6 0

The corresponding minimum and maximum velocities that the rocket experiences are 23.195m/s and 37.249m/s.

<h3>How to calculate the value?</h3>

The minimum value will be:

V(t) = 3t³ + (-24)t² + 54t

V(3.721) = 3(3.721)³ - 24(3.721)² + 54(3.721)

= 23.195m/s.

The maximum value will be:

V(.1613) = 3(1.613)³ - 24(1.613)² + 54(1.613)

= 37.249m/s

Learn more about velocity on:

brainly.com/question/1125420

#SPJ1

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3 years ago

A simple non-ideal Rankine cycle with water as the working fluid operates between the pressure limits of 15 MPa in the boiler an

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Answer:

The right solution is "28.45%".

Explanation:

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$h_4=0.7(2304.7)+340.5$

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$=\frac{2610.8-1953.83}{2610.8-1836.26}$

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The thermal efficiency of cycle will be:

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3 years ago

A manufacturer makes two types of drinking straws: one with a square cross-sectional shape, and the other type the typical round

Harlamova29_29 [7]

Answer:

$\frac{Q_{square}}{Q_{circle}} = 0.785$

Explanation:

given data

types of drinking straws

square cross-sectional shape
round shape

solution

we know that both perimeter of the cross section are equal

so we can say that

perimeter of square = perimeter of circle

4 × S = π × D

here S is length and D is diameter

S = $\frac{\pi D}{4}$ ....................1

and

ratio of flow rate through the square and circle is here

$\frac{Q_{square}}{Q_{circle}} = \frac{AV^2}{AV^2}$

$\frac{Q_{square}}{Q_{circle}} = \frac{S^2}{\frac{\pi D^2}{4}}$

$\frac{Q_{square}}{Q_{circle}} = \frac{(\frac{\pi D}{4})^2}{\frac{\pi D^2}{4}}$

$\frac{Q_{square}}{Q_{circle}} = \frac{\pi }{4}$

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4 years ago