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3 years ago

8

Water flows at a uniform velocity of 3 m/s into a nozzle that reduces the diameter from 10 cm to 2 cm. Calculate the water’s vel

ocity leaving the nozzle and the flow rate.

1 answer:

katrin2010 [14]3 years ago

4 0

Answer:

See the pictures attached

Explanation:

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A 225 MPa conducted in which the mean stress was 50 MPa and the stress amplitude was (a) Compute the maximum and (b) Compute the

tamaranim1 [39]

Answer:

Explanation:

Given data in question

mean stress = 50 MPa

amplitude stress = 225 MPa

to find out

maximum stress, stress ratio, magnitude of the stress range.

solution

we will find first maximum stress and minimum stress

and stress will be sum of (maximum +minimum stress) / 2

so for stress 50 MPa and 225 MPa

$\sigma _{m}$ = $\sigma _{maximum}$ + $\sigma _{minimum}$ / 2

50 = $\sigma _{maximum}$ + $\sigma _{minimum}$ / 2 ...........1

and

225 = $\sigma _{maximum}$ + $\sigma _{minimum}$ / 2 ...........2

from eqution 1 and 2 we get maximum and minimum stress

$\sigma _{maximum}$ = 275 MPa ............3

and $\sigma _{minimum}$ = -175 MPa ............4

In 2nd part we stress ratio is will compute by ratio of equation 3 and 4

we get ratio = $\sigma _{minimum}$ / $\sigma _{maximum}$

ratio = -175 / 227

ratio = -0.64

now in 3rd part magnitude will calculate by subtracting maximum stress - minimum stress i.e.

magnitude = $\sigma _{maximum}$ - $\sigma _{minimum}$

magnitude = 275 - (-175) = 450 MPa

3 0

3 years ago

Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determ

deff fn [24]

Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

<u>Simple cubic lattice</u>

<u /> $a=2r$

Now,

The unit cell volume will be:

$=a^3$

$=(2r)^3$

$=8r^3$

At one atom per cell, atom volume will be:

$=(1)\times (\frac{4 \pi r^3}{3})$

Then the ratio will be:

$Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent$

$=52.4 \ percent$

(b)...

<u>Diamond lattice</u>

The body diagonal will be:

$d=8r=a\sqrt{3}$

$a=\frac{8}{\sqrt{3}}r$

The unit cell volume will be:

$=a^1$

$=(\frac{8r}{\sqrt{3}})^1$

At eight atom per cell, the atom volume will be:

$=8(\frac{4 \pi r^1}{3})$

Then the Ratio will be:

$Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent$

$=34 \ percent$

Note: percent = %

5 0

3 years ago

How a single force is resolved along the perpendicular axis acting an angle theta with horizontal?

Nataly [62]

Answer:

A single force, which is acting at angle θ from a horizontal axis, can be resolved into components which act along the perpendicular axis.

Consider the perpendicular axis x and y, where x represents the horizontal axis and y represents vertical axis.

The Force is resolved into 2 parts, one acts along x-axis and is represent by X. The other acts along y-axis and is represented by Y.

From the diagram we can see that the Force and its components X and Y makes up a right angles triangle, where θ is the angle from the x-axis

<h3 /><h3>Find X:</h3>

We know that:

cosθ = Base/Hypotenuse

cosθ = X/F

X = Fcosθ

<h3>Find Y:</h3>

We know that:

sinθ = Perpendicular/Hypotenuse

sinθ = Y/F

Y = Fsinθ

<h3>Relation of Force and its Components:</h3>

Force F can be represent by:

F = Fcosθ (along x-axis) + Fsinθ (along y-axis)

As they form a right angled triangle, we can use Pythagoras Theorem to show the relation between Force and its components.

Hypotenuse² = Base² + Perpendicular²

F² = X² + Y²

F² = (Fcosθ)² + (Fsinθ)²

$F = \sqrt{(F\cos\theta)^2+(Fsin\theta)^2}$

Where θ can be found by using any of the trignometric functions.

6 0

3 years ago

If an individual is caught smoking in high school, what aspect of life would the differential association theorist be interested

Sauron [17]

The aspect of life that would the differential association theorist be interested in order to understand how that person started smoking is option a: smoking habits of peers, family, and friends.

<h3>Is smoking a habit or a lifestyle?</h3>

The act of Smoking is known to be a hard habit that is said to be difficult to break for a lot of reasons.

Note that it is one where a person is said to be only nicotine addictive, but smokers are said to be the smoke multiple times a day.

Therefore, The aspect of life that would the differential association theorist be interested in order to understand how that person started smoking is option a: smoking habits of peers, family, and friends

Learn more about smoking habits from

brainly.com/question/15967133

#SPJ1

See full question below

If an individual is caught smoking in high school, what direction would a differential association theorist go in examining how that person started smoking?

smoking habits of peers, friends, and family

strain caused by society's structure that leads to smoking

the student's self-control

how this student was identified when everyone is equally susceptible

7 0

2 years ago

Which of the following uses pressure and flow to transmit power from one location to another?

lord [1]

Answer:

fluid power

Explanation:

fluids commonly used in fluid power are Oil, Water, Air, CO², and Nitrogen gas, fluid power is commonly confused with hydraulic power, which only uses liquids, fluid power uses either liquids or gases

5 0

2 years ago