Forces exerted by the jet on the plate is=3976N
<h3>How to calculate forces exerted by the jet on the plate?</h3>
A force is an effect that can change the motion of an object. A force can generate an object with mass to change its velocity, i.e., to accelerate. Force can also be explained intuitively as a push or a pull. A force has both volume and direction, making it a vector amount.
A jet of water 75m in diameter
velocity = 30m/s
The forces exerted by the jet on the plate is
F=1000×44178×10^-3×30²
=3976N
the jet on the plate work done by Is zero .
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Answer:
1. It is a good practice to fully define a sketch to avoid having erroneous dimensions on the faces of a solid, this avoids that when it is required to make an assembly with the drawn part appear assembly errors.
2. The 2D sketch should always be done on a plane, so solidworks would ask you to select a plane on which you want to make the sketch, on the other hand, if it is a 3D sketch, solidworks allows you to do it without the need for Select any plane.
The controller determines if a(n) error exists by calculating the difference between the SP and the PV.
<h3>How does a
controller work in control system?</h3>
The Control system is one where it entails if the output is one that has an effect on the input quantity.
So it uses the PV(Process Variable) set against the SP(Setpoint) to know if an error exists.
So, The controller determines if a(n) error exists by calculating the difference between the SP and the PV.
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Answer and Explanation:
clear all; close all;
N=512;
t=(1:N)/N;
fs=1000;
f=(1:N)*fs/N;
x= sin(2*pi*200*t) + sin(2*pi*400*t);
y= sin(2*pi*200*t) + sin(2*pi*900*t);
for n = 1:20
a(n) = (2/N)*sum(x.*(cos(2*pi*n*t)))
b(n) = (2/N)*sum(x.*(sin(2*pi*n*t)))
c(n) = sqrt(a(n).^2+b(n).^2)
theta(n) =-(360/(2*pi))*atan(b(n)./a(n));
end
plot(f(1:20),c(1:20),'rd');
disp([a(1:4),b(1:4),c(1:4),theta(1:4)])
Answer:
using calculations Heat losses will be 4512 J
