Answer:
The Euler buckling load of a 160-cm-long column will be 1.33 times the Euler buckling load of an equivalent 120-cm-long column.
Explanation:
160 - 120 = 40
120 = 100
40 = X
40 x 100 / 120 = X
4000 / 120 = X
33.333 = X
120 = 100
160 = X
160 x 100 /120 = X
16000 / 120 = X
133.333 = X
Circle because it’s round and we all love round things
Answer:
Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22
Explanation:
Assuming a = 2b
Attached below is the required steps to the solution
The cutoff frequencies for the first ten modes of a rectangular waveguide listed in ascending order is :
Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22
Answer:
Part a : The SI unit of σ is Pascal.
Part b : The pressure is 414.28 psi.
Explanation:
Part a
The equation is given as

As per the dimensional analysis
![M=[N-m]\\y=[m]\\l=[m^4]](https://tex.z-dn.net/?f=M%3D%5BN-m%5D%5C%5Cy%3D%5Bm%5D%5C%5Cl%3D%5Bm%5E4%5D)
So the equation becomes
![\sigma =\frac{[N-m][m]}{[m^4]}\\\sigma =\frac{[N][m^2]}{[m^4]}\\\sigma =\frac{[N]}{[m^{4-2}]}\\\sigma =\frac{[N]}{[m^{2}]}\\](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Cfrac%7B%5BN-m%5D%5Bm%5D%7D%7B%5Bm%5E4%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%5Bm%5E2%5D%7D%7B%5Bm%5E4%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%7D%7B%5Bm%5E%7B4-2%7D%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%7D%7B%5Bm%5E%7B2%7D%5D%7D%5C%5C)
As the dimensions are of pressure so the SI unit of σ is Pascal.
Part b

Pressure in US customary base units is given in psi so

So

So the pressure is 414.28 psi.