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exis [7]
1 year ago
8

Plssssssssssssssssssssssssssssssssss

Mathematics
1 answer:
Lostsunrise [7]1 year ago
3 0
<h2><u>Quadrilateral</u></h2>

<h3>Classify the quadrilateral in as many ways as possible.</h3>

Shown in the figure, all the measurements of each sides is different, so it is only a quadrilateral. Square has four equal sides and angles, rhombus has only four equal sides, and a parallelogram whose opposite sides are parallel.

<u>Answer:</u>

  • <u>C. Quadrilateral</u>

<em>Picture 1 (Rhombus)</em>

<em>Picture </em><em>2</em><em> </em><em>(Square)</em>

<em>Picture 3 (Parallelogram)</em>

<em>Picture 4 (Quadrilateral)</em>

Wxndy~~

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Triangle ABC is similar to triangle QRS by the AA Similarity Postulate. Also, m∠A = 32° and m∠S = 102°. What is m∠B?
nignag [31]
The sum of interior angles of any polygon is:

s=180(n-2)

Since we are dealing with a triangle:

s=180(3-2)

s=180°

That is, the sum of angles of any triangle is 180°.

In this case we are given two angles with measures of 32° and 102° so

a+b+c=180

32+b+102=180 combine like terms on left

b+134=180  subtract 134 from both sides

b=46°
5 0
2 years ago
Hansel opened a bank account. He deposited $52.50 into his account every month for 10 months. He used $20.50 every month to pay
Maksim231197 [3]

$52.50 and subtract $20.50 to get $32 and multiply that by 10 (months) to get $320 and divide it by 2 and your final answer is; $160.00

8 0
2 years ago
Read 2 more answers
What are the first and last deciles of the standard Normal distribution?
aliya0001 [1]

My best Guess is

1.282 for upper . , -1.282 for lower.

Hope this Helps

-Dante

5 0
3 years ago
Find the equation of the line that passes through the point of intersection of x + 2y = 9 and 4x -2y = -4 and the point of inter
Rudik [331]

Answer:

y=-6x+10

Step-by-step explanation:

The point of intersection of

x+2y=9...eqn1


and


4x-2y=-4...eqn2

is the solution of the two equations.


We add equation (1) and equation(2) to get,

x+4x+2y-2y=9+-4


\Rightarrow 5x=5


\Rightarrow x=1

We put x=1 into equation (1) to get,

1+2y=9

\Rightarrow 2y=9-1

\Rightarrow 2y=8

\Rightarrow y=4


Therefore the line passes through the point, (1,4).


The line also passes through the point of intersection of

3x-4y=14...eqn(3)

and

3x+7y=-8...eqn(4)

We subtract equation (3) from equation (4) to obtain,

3x-3x+7y--4y=-8-14


\Rightarrow 11y=-22

\Rightarrow y=-2


We substitute this value into equation (4) to get,

3x+7(-2)=-8


3x-14=-8


3x=-8+14


3x=6

x=2

The line also passes through

(2,-2)



The slope of the line is

slope=\frac{4--2}{1-2} =\frac{6}{-1}=-6


The equation of the line is

y+2=-6(x-2)

y+2=-6x+12


y=-6x+10 is the required equation





4 0
3 years ago
Give the domain and range of G={(6.0),(-9,-3),(1,-3)}
VashaNatasha [74]

Answer:

Step-by-step explanation:

D={ 6  , -9  , 1 }

R={  0  ,-3 }

7 0
3 years ago
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