Answer:
The tangential speed of the tack is 8.19 m/s.
Explanation:
The wheel rotates 3.37 times a second that means wheel complete 3.37 revolutions in a second. Therefore, the angular speed ω of the wheel is given as follows:
![\omega =3.37rev/s \times(\frac{2\pi rad}{1s} )\\\\=21.174rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D3.37rev%2Fs%20%5Ctimes%28%5Cfrac%7B2%5Cpi%20rad%7D%7B1s%7D%20%29%5C%5C%5C%5C%3D21.174rad%2Fs)
Use the relation of angular speed with tangential speed to find the tangential speed of the tack.
The tangential speed v of the tack is given by following expression
v = ω r
Here, r is the distance to the tack from axis of rotation.
Substitute 21.174 rad/s for ω, and 0.387 m for r in the above equation to solve for v.
v = 21.174 × 0.387
v = 8.19m/s
Thus, The tangential speed of the tack is 8.19 m/s.
She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.
What is focal length?
The focal length is a measure of how strongly the system converges or diverges light.
A positive focal length indicates that a system converges light, while a negative focal length indicates that the system diverges light.
For a standard rectilinear lens,
FOV = 2 arctan (x/2f)
FOV ∝ 1 / f
where x is the diagonal of the film.
Focal length (f) and field of view (FOV) of a lens are inversely proportional.
From the equation we can say that,
A shorter focal length gives you a wide angle of view which allows more view to fit in the frame.
Hence,
She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.
Learn more about focal length here
<u>brainly.com/question/13885819</u>
<u />
#SPJ4
Answer:
Dx = -0.5
Dy = -0.25
Explanation:
Two vectors are given in rectangular components form as follows:
A = i + 6j
B = 3i - 7j
It is also given that:
A - B - 4D = 0
so, we solve this to find D vector:
(i + 6j) - (3i - 7j) - 4D = 0
- 2i - j = 4D
D = - (2/4)i - (1/4)j
D = - (1/2)i - (1/4)j
<u>D = - 0.5i - 0.25j</u>
Therefore,
<u>Dx = -0.5</u>
<u>Dy = -0.25</u>
Average speed is the ratio of total distance moved by Chi in total time interval
So here we will have
Total distance = 100 m + 400 m
![d = 500 m = 0.5 km](https://tex.z-dn.net/?f=d%20%3D%20500%20m%20%3D%200.5%20km)
Total time taken = 5 min + 15 min = 20 min
![T = \frac{20}{60} = \frac{1}{3} hour](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B20%7D%7B60%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20hour)
now by the formula of average speed we know that
![v_{avg} = \frac{d}{T}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7Bd%7D%7BT%7D)
![v_{avg} = \frac{0.5 km}{1/3 h}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7B0.5%20km%7D%7B1%2F3%20h%7D)
![v_{avg} = 1.5 km/h](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%201.5%20km%2Fh)
so average speed will be 1.5 km/h
PE= 3kg x 10N/kg x 10m
= 300J