Question

You have a beaker with a layer of olive oil floating on top of water. A ray of light travels through the oil and is incident on the water with an angle of 73.4°. Using the index of refraction of the oil as 1.470 and the index of refraction of water as 1.333, determine the critical angle in oil for the oil-water interface.

Answer 1

Answer:

$65.07^{\circ}$

Explanation:

The critical angle in oil for the oil-water interface refers to the angle for which the light ray is totally reflected.

Angle of incidence = 73.4°

Angle of refraction = 1.470°

Index of refraction = 1.333

$\theta_c=\sin^{-1}\left ( \frac{n_2}{n_1} \right )$

Here, $\theta_c$ refers to the critical angle.

$n_2$ is an index of refraction

$n_1$ is angle of refraction

$\theta_c=\sin^{-1}\left ( \frac{1.333}{1.47} \right )=65.07^{\circ}$

Here, angle of incidence is more than the critical angle,

light undergoes total internal reflection.