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evablogger [386]

3 years ago

14

5.3 × 1012 kg satellite is 1,800 m from another satellite that has a mass of 3.5 × 108 kg. What is the gravitational force betwe

en the satellites? 3.82 × 104 N 6.87 × 107 N 5.72 × 1014 N 1.03 × 1018 N

2 answers:

Sphinxa [80]3 years ago

8 0

The answer is: 3.82 × 10^4 N

maria [59]3 years ago

4 0

The answer is: 3.82 × 10^4 N. Hope this helps!

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List one way to take advantage of creating even more kinetic energy on this particular technologically advanced field

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Kinetic energy can be used to develop electric energy which can be used as electricity.

<u>Explanation:</u>

The kinetic energy can be harnessed; much like some hydro power technologies harness water movement. A way to convert this kinetic energy into electric energy is through piezoelectric. By applying a mechanical stress to a piezoelectric crystal or material an electric current will be created and can be harvested.

Kinetic energy is also generated by the human body when it is in motion. Studies have also been done using kinetic energy and then converting it to other types of energy, which is then used to power everything from flashlights to radios and more.

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Which copper wire would have the lowest resistance?

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B. The resistance is directly proportional to length and inversely proportional to cross sectional area

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A girl at an airport rolls a ball north on a moving walking that moves east. If the ball’s speed with respect to the walkway is

sweet-ann [11.9K]

We have to add two vectors.

Vector #1: 0.15 m/s north

Vector #2: 1.50 m/s east

Their sum:

Magnitude: √(0.15² + 1.50²)

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Magnitude = √2.2725

Magnitude = <em>1.5075 m/s</em>

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3 years ago

1 A 75-g ball is projected from a height of 1.6 m with a horizontal velocity of 2 m/s and bounces from a 400-g smooth plate supp

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Answer with explanation:

We are given that

Mass of ball, $m_1=$ 75 g= $\frac{75}{1000}=0075kg$

1 kg=1000 g

Height, $h_1=1.6 m$

$h_2=0.6 m$

Horizontal velocity, $v_x=2 m/s$

Mass of plate $m_2=400 g=\frac{400}{1000}=0.4 kg$

a.Initial velocity of plate, $u_2=0$

Velocity before impact= $u_1=\sqrt{2gh_1}=\sqrt{2\times 9.8\times 1.6}=5.6m/s$

Where $g=9.8 m/s^2$

Velocity after impact, $v_1=\sqrt{2gh_2}=\sqrt{2\times 9.8\times 0.6}=3.4m/s$

According to law of conservation of momentum

$m_1u_1+m_2u_1=-m_1v_1+m_2v_2$

Substitute the values

$0.075\times 5.6+0=-0.075\times 3.4+0.4v_2$

$0.4v_2=0.075\times 5.6+0.075\times 3.4$

$v_2=\frac{0.075\times 5.6+0.075\times 3.4}{0.4}=1.69 m/s$

Velocity of plate=1.69 m/s

b.Initial energy= $\frac{1}{2}m_1v^2_x+m_1gh_1=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 1.6=1.326 J$

Final energy= $\frac{1}{2}m_1v^2_x+m_1gh_2+\frac{1}{2}m_2v^2_2$

Final energy= $\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 0.6+\frac{1}{2}(0.4)(1.69)^2=1.162 J$

Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J

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Which of the following epidermal cells are the sensory receptors for touch?

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Merkel cells are the sensory receptors for touch.

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3 years ago