In collision of the steel ball and the steel plate, the collision is an inelastic collision and there is loss in the kinetic energy.
<h3>What are collisions?</h3>
Collisions occur when two objects that are moving in the same directions or in different direction meet each other and collide.
There are two types of collisions:
- elastic collision - the kinetic energy is conserved
- inelastic collision - there is a loss in kinetic energy
In the collision of the steel ball and the steel plate, there is loss in the kinetic energy of the steel ball which is converted to sound energy.
In conclusion, the collision of the steel and steel plate is an inelastic collision.
Learn more about collisions at: brainly.com/question/7694106
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Answer:
.00135 j
Explanation:
K.E. = 1/2 m v^2
= 1/2 * .03 * .3^2 = .00135 j
mass of iron block given as

density of iron block is

now the volume of the iron piece is given as


Now when this iron block is complete submerged in oil inside the beaker the buoyancy force on the iron block will be given as

here we know that
= density of liquid = 916 kg/m^3


Now for the reading of spring balance we can say the spring force and buoyancy force on the block will counter balance the weight of the block at equilibrium



So reading of spring balance will be 16.45 N
Now for other scale which will read the normal force of the surface we can write that normal force on the container will balance weight of liquid + container and buoyancy force on block



So the other scale will read 36.47 N