Answer:
(d) an orange fringe at 0°, yellow fringes at ±50°, and red fringes farther out
Explanation:
The available multiple choice to the question is:
(a) only red fringes at 0° and ±50°
(b) only yellow fringes at 0°and ±50°
(c) only orange fringes at 0∘ and ±50°
(d) an orange fringe at 0°, yellow fringes at ±50° , and red fringes farther out,
(e) an orange fringe at 0°, yellow fringes at ±50°, and red fringes closer in.
Further Explanation:
In diffraction there is a spot at 0° for all wavelengths, so the red fringe and yellow fringe will combine there to make orange fringe. However, the angle of diffraction increase with an increase in wavelength. The red fringer has a longer wavelength than the yellow fringe, so the yellow fringe will be at ±50°, and the red fringe farthers out.
<h2>Answer: Medium
</h2>
The medium is the main factor that differentiates a mechanical wave from an electromagnetic wave, since the first can not propagate without its existence, while the second can propagate regardless of whether the medium exists or not.
In addition, it is the medium that will define, the propagation speed of the wave, according to its specific physical characteristics.
Therefore, the <u>correct answer</u> is a.
Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.
In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.
Answer:
Counterclockwise
Explanation:
We need to calculate the clocwkise and the counterclockwise torque.
The clockwise torque is the one generated by the child sitting on the right. This torque is given by:

where
is the force exerted by the child (his weight)
d = 1.8 m is the distance from the pivot point
So, the clockwise torque is

The counterclockwise torque is the one generated by the adult pushing on the left, and it is given by

where
F = 151 N is the force applied
d = 3.0 m is the distance from the pivot
Substituting,

So, the net torque is

And since the counterclockwise momentum is greater than the clockwise one, the teeter-totter will rotate counterclockwise.