Answer:
A.) 1430 metres
B.) 80 seconds
Explanation:
Given that the train accelerates from rest at 1.1m/s^2 for 20s. The initial velocity U will be:
U = acceleration × time
U = 1.1 × 20 = 22 m/s
It then proceeds at constant speed for 1100 m
Then, time t will be
Time = distance/ velocity
Time = 1100/22
Time = 50 s
before slowing down at 2.2m/s^2 until it stops at the station.
Deceleration = velocity/time
2.2 = 22/t
t = 22/2.2
t = 10s
Using area under the graph, the distance between the two stations will be :
(1/2 × 22 × 20) + 1100 + (1/2 × 22 × 10)
220 + 1100 + 110
1430 m
The time taken between the two stations will be
20 + 50 + 10 = 80 seconds
Explanation :
Using the law of conservation of energy
When two cars collide with each other then the momentum is same before collision and after collision but energy is changed after collision in form of heat and sound.
We know this collision is inelastic collision.
In Inelastic collision, when two objects collide with each other then the momentum is conserved but kinetic energy is not conserved.
This question is incomplete, the complete question is on the image uploaded along this answer.
Answer:
the potential at point B is 5 V, Option d) is the correct answer
Explanation:
Given that;
from the image;
R = 3 + 4 + 5 = 12 Ω
so I = 12/12 = 1 A
Q = 0 + 12 = 12 V
now
VA - VQ = - I × 3 = -3 V
VA = VQ - 3 = 12 - 3 = 9 V
VB - VA = - I × 4Ω = - 4 V
⇒VB = VA - 4 = 9 V - 4 V = 5 V
Therefore the potential at point B is 5 V
Option d) is the correct answer
Answer:
1) 341 Hz
Explanation:
When a string vibrates, it can vibrate with different frequencies, corresponding to different modes of oscillations.
The fundamental frequency is the lowest possible frequency at which the string can vibrate: this occurs when the string oscillate in one segment only.
If the string oscillates in n segments, we say that it is the n-th mode of vibration, or n-th harmonic.
The frequency of the n-th harmonic is given by

where
n is the number of the harmonic
is the fundamental frequency
Here we have:
is the frequency of the 3rd harmonic
So the fundamental frequency is

And so, the frequency of the 2nd harmonic is:
