All categories

2 years ago

Complete this paragraph, which describes an ice cube changing from a solid to a liquid to a gas

Physics

1 answer:

Burka [1]2 years ago

5 0

An ice cube changing from a solid to a liquid is melting and then to a gas is vaporization.

<h3>What is a change of state process?</h3>

A change of state process describes a process whereby a substance changes from one physical state to another.

The change of state processes are:

melting - solid changing to liquid
vaporization - liquid changing to gas

Therefore, an ice cube changing from a solid to a liquid is melting and then to a gas is vaporization.

Learn more about change of state at: brainly.com/question/9007095

#SPJ1

You might be interested in

A coin is dropped from a height of 188 meters. Neglecting air resistance, how much time (in seconds) was the coin in the air?

Marina CMI [18]

Answer:

$t=6.19s$

Explanation:

With a initial velocity is zero, kinematics equation is:

$y=1/2*g*t^2$

$t=\sqrt{2y/g}=\sqrt{2*188/9.81}=6.19s$

8 0

3 years ago

A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/srev/s . The wheel can be consi

vagabundo [1.1K]

Answer:1.7 rev/s

Explanation:

Given

Frequency of wheel $N_1=2\ rev/s$

angular speed $\omega_1=2\pi N_1=4\pi\ rad/s$

mass of wheel $m_1=4.5\ kg$

diameter of wheel $d_1=0.30\ m=30\ cm$

radius of wheel $r_1=\frac{d_1}{2}=\frac{30}{2}=15\ cm$

mass of clay $m_2=2.8\ kg$

the radius of the chunk of clay $r_2=8\ cm$

Moment of inertia of Wheel

$I_1=\dfrac{m_1r_1^2}{2}=\dfrac{4.5\times 15^2}{2}\ kg-cm^2$

Combined moment of inertia of wheel and clay chunk

$I_2=\dfrac{m_1r_1^2}{2}+\dfrac{m_2r_2^2}{2}=\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2}\ kg-cm^2$

Conserving angular momentum

$\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi$

Common frequency of wheel and chunk of clay is

$\Rightarrow N_2=\dfrac{4\pi \times 0.849}{2\pi}=1.698\approx 1.7\ rev/s$

5 0

3 years ago

PLEASE HELP ME! IM TIMED

viktelen [127]

The last answer I think

3 0

3 years ago

1. A 65 kg student, starting from rest, slides down an 16.2 m high water slide. On the way down, friction does 5700 J of work on

GuDViN [60]

Answer:

11.94

Explanation:

Remark

Find the Potential Energy at the top.

Givens

m = 65 kg

h = 16.2 m

g = 9.81

PE = 65 * 9.81 * 16.2

PE = 10329.93

The tricky part is what do you do about Friction?

Formula

PE = Friction + KE

Solution

PE = 10329.93 Joules

Friction = 5700 Joules

Find the KE

10329.93 = 5700 + KE

KE = 10329.93 - 5700

KE = 4629.93

Find V from the KE formula

KE = 4629.93

m = 65

KE = 1/2 m v^2

KE = 1/2 65 v^2

4629.93 = 1/2 65 v^2

v^2 = 142.46

v = √142.46

v = 11.94

4 0

3 years ago

How does sound travel?

Doss [256]

Answer:

Sound vibrations travel in a wave pattern, and we call these vibrations sound waves. Sound waves move by vibrating objects and these objects vibrate other surrounding objects, carrying the sound along. ... Sound can move through the air, water, or solids, as long as there are particles to bounce off of.

Explanation:

8 0

3 years ago

Read 2 more answers