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aivan3 [116]
3 years ago
14

A testable prediction is a(n) ______. Group of answer choices a. hypothesis b. experiment c. exercise d. variable

Physics
2 answers:
kicyunya [14]3 years ago
7 0

Answer :A testable prediction is also known as a hypothesis.

Explanation: I think

telo118 [61]3 years ago
5 0

A testable prediction is a hypothesis. <em>(a)</em>

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Work equal to 136.0 Joules is expanded in moving 8.5*10^18 electrons between two points in an electric circuit. What potential d
kenny6666 [7]
Voltage = joules/coulomb

1 coulomb = 6.25 x 10^18 electrons
8.5 x 10^18 electrons = 1.36 coulombs

136 joules / 1.36 coulombs = 100 volts
===================================
The statement regarding the ball is false. Any object that's not hanging from something
or resting on something is accelerating downward on account of gravity. No matter what
direction you throw the ball, or how hard, its acceleration is 9.8 meters per second^2
directed downward, from the instant it leaves your hand until it hits the ground.
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3 years ago
A globe is an example of a physical model true or false
mars1129 [50]
True. Because you can touch it and it's physically real.
4 0
4 years ago
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With a force of 5 Newton's Amanda pushes the stacks of books to the right. At the same time Jeremih her little brother pushes th
Fynjy0 [20]

Alright, so solving for the net force is a rather simple and easy step. I want to briefly explain how you determine the net force, but before I do, let's examine the problem together. What has been provided to us? What direction is it going? Well, we can look at the information!

Amanda's Force: 5 N

Jeremiah's Force: 10 N

They're both pushing on the books, but in different directions. Left and right. If Amanda is pushing the books to the right 5 newtons, and Jeremiah is pushing the books to the left with 10 newtons, that means the net force is 5. The book is being pushed to the left! We can say that because Jeremiah's force is much larger than his sisters.

We can determine the net force from the following;

Net Force → 10 N - 5 N = 5 N

In conclusion, your answer should be a total of five (5) newtons

4 0
3 years ago
Read 2 more answers
In a perfectly elastic collision between two perfectly rigid objects
ipn [44]

Both the total momentum and the total kinetic energy are conserved

Explanation:

- In a collision between two or more objects, if there are no external forces acting on the system (isolated system), the total momentum of the objects is always conserved. This is called principle of conservation of momentum, and can be written as follows:

mu+MU = mv+MV

where

m, M are the masses of the two objects

u, U are the initial velocities of the two objects

v, V are the final velocities of the two objects

- The total kinetic energy, however, is not always conserved. In fact, we have two types of collision:

1) In a perfectly elastic collision, the total kinetic energy of the objects is conserved. This means that we can write the following equation:

\frac{1}{2}mu^2 + \frac{1}{2}MU^2 = \frac{1}{2}mv^2+\frac{1}{2}MV^2

2) In an inelastic collision, the total kinetic energy of the object is NOT conserved. This means that part of the total kinetic energy is "lost", converted into other forms of energy (mainly thermal energy, due to the presence of frictional forces within the system). The most extreme case is called perfectly inelastic collision, in which the two objects stick together after the collision, and there is the maximum loss of kinetic energy.

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

LearnwithBrainly

7 0
4 years ago
32g of water at 60°C is poured into 60g of cold water at 15°C, which is contained in a
Anestetic [448]

Explanation:

Let thermal capacity of the vessel be C' J K-1

Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J

Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J

Heat energy taken by vessel = C' x (30 - 20) = 10 C' J

If there is no loss of heat energy,

Heat energy given by hot water = Heat energy taken by cold water and vessel

or 5040 = 2100 + 10 C'

or 10 C' = 2940

or C'= 294 J K-1

Thus, thermal capacity of vessel = 294 J K-1.

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