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3 years ago

A testable prediction is a(n) ______. Group of answer choices a. hypothesis b. experiment c. exercise d. variable

Physics

2 answers:

kicyunya [14]3 years ago

7 0

Answer :A testable prediction is also known as a hypothesis.

Explanation: I think

telo118 [61]3 years ago

5 0

A testable prediction is a hypothesis. <em>(a)</em>

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A student performs a lab measuring the velocities of toy cars of different masses

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The answer is Car 1 and Car 2.

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Assume an axon has an internal diameter of 1μm and a myelin sheath 1μm thick. The internal specific resistance is 100 Ω cm. For

SpyIntel [72]

Answer:

$1.27\times 10^{12}\Omega/m$

Explanation:

We are given that

Diameter=d= $\mu m$

Thickness= $1\mu m$

Radius= $r=\frac{d}{2}=\frac{1}{2}\mu m=0.5\times 10^{-6} m$

Using $1\mu m=10^{-6} m$

Dielectric constant=8

Resistance = $R=2\times 10^5\Omega cm^2$

Internal specific resistance=r=100 ohm cm= $100\times \frac{1}{100}\Omega-m=1\Omega m$

Using 1 m=100 cm

Internal resistance per unit length= $\frac{r}{A}=\frac{1}{\pi r^2}=\frac{1}{3.14\times (0.5\times 10^{-6})^2}=1.27\times 10^{12}\Omega/m$

Using $\pi=3.14$

Internal resistance per unit length= $1.27\times 10^{12}\Omega/m$

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3 years ago

A machine is currently set to a feed rate of 5.921 inches per minute (IPM). Te machinist changes this setting to 6.088 IPM. By h

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Answer:

By 16.7% or 0.167 IPM

Explanation:

Substracting the final IPM (6.088) to the initial IPM (5.921) gives us the net difference, which is how much did it increase in IPM. Multiplying this number by 100 gives us the percentual increase in the feed rate.

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PLEASE HELP FAST The object distance for a convex lens is 15.0 cm, and the image distance is 5.0 cm. The height of the object is

IgorLugansk [536]

Answer:

The image height is 3.0 cm

Explanation:

Given;

object distance, $d_o$ = 15.0 cm

image distance, $d_i$ = 5.0 cm

height of the object, $h_o$ = 9.0 cm

height of the image, $h_i$ = ?

Apply lens equation;

$\frac{h_i}{h_o} = -\frac{d_i}{d_o}\\\\ h_i = h_o(-\frac{d_i}{d_o})\\\\h_i = -9(\frac{5}{15} )\\\\h_i = -3 \ cm$

Therefore, the image height is 3.0 cm. The negative values for image height indicate that the image is an inverted image.

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3 years ago